Preventing IndexOutOfRangeException on arrays

Question

I looking for a way to prevent IndexOutOfRangeException when I try to access a specific array index.

I have a generic code that some times has values at array[index], and other times there is not.

so, before trying to get its value I have tried these checks:

if(array[index] != null) {
    ... Do Stuff
}

Also tried:

if(!String.IsNullOrEmpty(array[index])) {
    ... Do Stuff
}

They all trows an IndexOutOfRangeException

How could I perform this check?

Why is your code attempting to access memory outside the bounds of the array in the first place? Don't try and catch an error.. remove the error. — Simon Whitehead
– Simon Whitehead, Commented Feb 15, 2013 at 1:31
Just fixed. My code need some bug fixes. This is one of them. I was just curious why I was not able to check for a null index. Thanks — Guilherme Longo
– Guilherme Longo, Commented Feb 15, 2013 at 1:36

SLaks · Accepted Answer · 2013-02-15 01:30:46Z

12

Very simple:

if (index < array.Length)

answered Feb 15, 2013 at 1:30

SLaks

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3 Comments

Simon Whitehead Over a year ago

While this is correct.. I feel like it should be within the loop initializer.. instead of being checked from within (I'm assuming it's a loop).

Guilherme Longo Over a year ago

Thanks. It worked. I have to fix my code to prevent this. I was just curious why cheking for null was not working

SLaks Over a year ago

@GuilhermeLongo: Array[999] isn't null; rather, it doesn't exist at all. The exception when you get the value in the first place, before the comparison.

codingbiz · Accepted Answer · 2013-02-15 01:43:27Z

0

You could also use try... catch to suppress the error. Brute?

try
{
   var x = array[index];
}
catch(Exception ex)
{
}

And better

if(array.Length > index)
   var x = array[index];

answered Feb 15, 2013 at 1:43

codingbiz

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