I have two functions:
Function1
{
Function2
return 1
}
Function2
{
return 0
}
After executing Function1 it should return 1, but it returns 0. Why is that?
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I really don't understand what you're asking. What are you expecting Function1 to return and what is it returning?zdan– zdan2013-04-11 18:11:26 +00:00Commented Apr 11, 2013 at 18:11
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after executing Function1 it shoulf return value 1 but it returns value 0.JustSam– JustSam2013-04-11 18:18:02 +00:00Commented Apr 11, 2013 at 18:18
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How are you calling Function1 and how are you detecting its return value?zdan– zdan2013-04-11 18:55:38 +00:00Commented Apr 11, 2013 at 18:55
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2 Answers
PowerShell "return values" don't really work the way you'd be used to from other languages. The important thing to remember is that all output is captured and returned. The return statement is basically just a logical exit point.
For example:
Function Return-Zero {
return 0
}
Function Return-One {
Return-Zero
return 1
}
Return-One
Since the return value of Return-Zero was not stored in a variable, it is part of the output. Running the above will have the output:
0
1
...which is probably what you're getting. If you store the return of Return-Zero in a variable, it is not part of the output.
Function Return-Zero {
return 0
}
Function Return-One {
$var = Return-Zero
return $var
}
Return-One
Output of the above is 0.
2 Comments
FrozenLand
Thank you! I was having the same problem. So do you know of any way to actually return the thing that you want, discarding other outputs. Outputs are hard to capture in your way because you dont know if a statement will return any value or not.
Kevin Richardson
The actual code would dictate the best way to go about it. If you have an example to post, that would be helpful.
Are you sure it continues to run, and that it only returns 0? It should return 0 (the return from function 2), then return 1, and exit.
1 Comment
JustSam
no it returns 0 and continues to run..if m not wrong sine the Funtion1 has got return 0 from Function2 call it ignores the return 1...is that possible...have i missed something...but when i assign the Function2 cqll in Funtion1 to a variable the funtion1 exits properly...y this strange behaviour...is there a precedence of return value or something...