count = 0
i = 0
while count < len(mylist):
newlist.append(mylist[i + 1])
newlist.append(mylist[i + 2])
# ...
count = count + 1
i = i + 12
I wanted to make the newlist.append() statements into a few statements.
7 Answers
No. The method for appending an entire sequence is list.extend().
>>> L = [1, 2]
>>> L.extend((3, 4, 5))
>>> L
[1, 2, 3, 4, 5]
answered May 18, 2013 at 6:43
Ignacio Vazquez-Abrams
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4 Comments
sparrow
'insert' functions as 'append' but adds to the beginning of the list. Is there a function to adding multiple values to the beginning of a list?
Ignacio Vazquez-Abrams
@sparrow: No. Slice-assign instead.
Charlie Parker
do you need the second input to be a list or can it just be each element separated by commas?
Ignacio Vazquez-Abrams
@CharlieParker: The argument to
list.extend() must be an iterable.You could also:
newlist += mylist[i:i+22]
Comments
mylist = [1,2,3]
def multiple_appends(listname, *element):
listname.extend(element)
multiple_appends(mylist, 4, 5, "string", False)
print(mylist)
OUTPUT:
[1, 2, 3, 4, 5, 'string', False]
Comments
L1 = [1, 2]
L2 = [3,4,5]
L1+L2
#Output
[1, 2, 3, 4, 5]
By using the (+) operator you can skip the multiple append & extend operators in just one line of code and this is valid for more then two of lists by L1+L2+L3+L4.......etc.
Comments
If you are adding the same element then you can do the following:
["a"]*2
>>> ['a', 'a']
Comments
Use a for loop, it might look like this:
for x in [1,2,7,8,9,10,13,14,19,20,21,22]:
new_list.append(my_list[i + x])
Comments
Pretty simple. Surprisingly in python, you can just use +=
myList += newListItems
Example
myList = [1,2]
myList += [3,4]
print(myList) # prints [1,2,3,4]
[]instead of(). Please post real working code.