Get java version from batch file

Question

How to get java version and want to get '6' out of java version from batch file. I tried below script, but it didn't work.

    REM check java exists using JAVA_HOME system variable

if "%JAVA_HOME%" == "" (
ECHO Installing java
start /w jdk.exe /s
SETX -m JAVA_HOME "C:\Program Files\Java\jdk1.6.0_31"
ECHO java installed successfully
) ELSE (
ECHO checking java version
goto check_java_version
)

REM check java version using JAVA_HOME system variable
:check_java_version
set PATH=%PATH%;%JAVA_HOME%\bin
for /f tokens^=2-5^ delims^=.-_^" %%j in ('%JAVA_HOME%/bin/java -version 2^>^&1') do set "jver=%%j%%k%%l%%m"
echo %jver%

JAVA_HOME has "C:\Program Files\Java\jdk1.6.0_31" value.

npocmaka · Accepted Answer · 2014-04-25 17:46:24Z

21

for /f tokens^=2-5^ delims^=.-_^" %j in ('java -fullversion 2^>^&1') do @set "jver=%j%k%l%m"

This will store the java version into jver variable and as integer And you can use it for comparisons .E.G

if %jver% LSS 16000 echo not supported version

.You can use more major version by removing %k and %l and %m.This command prompt version.

For .bat use this:

@echo off
PATH %PATH%;%JAVA_HOME%\bin\
for /f tokens^=2-5^ delims^=.-_^" %%j in ('java -fullversion 2^>^&1') do set "jver=%%j%%k%%l%%m"

According to my tests this is the fastest way to get the java version from bat (as it uses only internal commands and not external ones as FIND,FINDSTR and does not use GOTO which also can slow the script). Some JDK vendors does not support -fullversion switch or their implementation is not the same as this one provided by Oracle (better avoid them).

edited Apr 25, 2014 at 17:46

answered Jul 18, 2013 at 4:45

npocmaka

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11 Comments

Bobby Rachel Over a year ago

How to print jver value. i tried with echo %jver%. its not working

npocmaka Over a year ago

try with *PATH %PATH%;%JAVA_HOME%\bin\* before the for loop

Bobby Rachel Over a year ago

getting error: it says *path is not a command. then for echo %jver% it says echo is off. i updated my question above. gave full script. just check it out plz.

npocmaka Over a year ago

remove the *.The bolding left one asteriks here...Will edit the answer

npocmaka Over a year ago

java.exe is not in the path. what is the result if you just write %JAVA_HOME%\bin\java.exe /?

|

Endoro · Accepted Answer · 2013-07-18 06:51:10Z

3

You can do this with awk:

>java -fullversion 2>&1|awk "{print $NF}"
"1.7.0_21-b11"

>java -fullversion 2>&1|awk -F\" "{print $(NF-1)}"
1.7.0_21-b11

Script example:

@ECHO OFF &SETLOCAL
FOR /f %%a IN ('java -fullversion 2^>^&1^|awk "{print $NF}"') DO SET "javaversion=%%a"
IF DEFINED javaversion (ECHO java version: %javaversion%) ELSE ECHO java NOT found

output is: java version: "1.7.0_21-b11"
awk for Windows

edited Jul 18, 2013 at 6:51

answered Jul 18, 2013 at 6:31

Endoro

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1 Comment

Endoro Over a year ago

@BobbyRachel script inserted.

cyril · Accepted Answer · 2016-08-18 09:13:34Z

1

it will be surly idiot but why do not just print JAVA_HOME path ?

answered Aug 18, 2016 at 9:13

cyril

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Comments

Richie · Accepted Answer · 2013-07-18 04:46:35Z

0

it should be java -version // if environment path is already set

or %JAVA_HOME%/bin/java -version //if path is not already set

answered Jul 18, 2013 at 4:46

Richie

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Comments

Magoo · Accepted Answer · 2013-07-18 04:47:00Z

0

Within a block statement, %var% would be echoed as the value of var BEFORE the block was entered.

Move the echo outside of the block or echo %%g or call echo %%javaver%% or invoke SETLOCAL enabledelayedexpansion and echo !javaver!

answered Jul 18, 2013 at 4:47

Magoo

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