Regex to split string

Question

I have this code which prints:

[( ?Random = <http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#Hello> ), ( ?Random = <http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#Bye> )]

I tried to split at [#] but it didnt work.

What should i put in split so that I can get as a result the part after # only: Hello, Bye

Query query = QueryFactory.create(queryString);
                     QueryExecution qe= QueryExecutionFactory.create(query, model);
                    ResultSet resultset = qe.execSelect();
                    ResultSet results = ResultSetFactory.copyResults(resultset); 
                    final ResultSet results2 = ResultSetFactory.copyResults(results);


                    System.out.println( "== Available Options ==" );
                    ResultSetFormatter.out(System.out, results, query);



    Scanner input = new Scanner(System.in);
    final String inputs;
    inputs = input.next();
    final String[] indices = inputs.split("\\s*,\\s*");

    final List<QuerySolution> selectedSolutions = new ArrayList<QuerySolution>(
            indices.length) {
        {
            final List<QuerySolution> solutions = ResultSetFormatter
                    .toList(results2);
            for (final String index : indices) {
                add(solutions.get(Integer.valueOf(index)));
            }
        }
    };

    System.out.println(selectedSolutions);

Mena · Accepted Answer · 2013-09-17 16:57:48Z

7

If I understand correctly, you only want to extract "Hello" and "Bye" from your input String through regex.

In which case, I would just use iterative matching of whatever's in between # and >, as such:

// To clarify, this String is just an example
// Use yourScannerInstance.nextLine to get the real data
String input = "[( ?Random = <http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#Hello> ), "
                + "( ?Random = <http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#Bye> )]";
// Pattern improved by Brian
// was: #(.+?)>
Pattern p = Pattern.compile("#([^>]+)>");
Matcher m = p.matcher(input);
// To clarify, printing the String out is just for testing purpose
// Add "m.group(1)" to a Collection<String> to use it in further code
while (m.find()) {
    System.out.println(m.group(1));
}

Output:

Hello
Bye

edited Sep 17, 2013 at 16:57

answered Sep 17, 2013 at 16:39

Mena

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9 Comments

Brian Over a year ago

+1, beat me to it, but use "#([^>]+)>", it can be much faster than using reluctant quantifiers.

Mena Over a year ago

@Brian thanks for the improvement tip and fair play! Will edit my answer now.

user2598911 Over a year ago

I want the output to be: Hello, Bye and if i use this I cant get results, because the string input = "..." you wrote is not always the same and changes depending on user input. (example type 1,2 and get different results from 3,4). However I always need to get the same part between # and >

Mena Over a year ago

@user2598911 sorry went to the gym. Yes, with yourArrayListInstance.add(matcher.group(1)) in this instance.

Mena Over a year ago

You're probably printing the ArrayList instead of each of its elements - I'd advise to take a look at the javadoc. Using m.group() will add the whole match; as said you want m.group(1) which will add what's between # and >.

|

Ruchira Gayan Ranaweera · Accepted Answer · 2013-09-17 16:53:28Z

2

You can try this

String[] str= your_orginal_String.split(",");

Then you can take the parts after # as follows

String[] s=new String[2];
int j=0;
for(String i:str){
    s[j]=i.split("#",2)[1];
    j++;
}

You may need some formatting. for resulting String[] s as follows

    String str = "[( ?Random = <http://www.semanticweb.org/vassilis
                   /ontologies/2013/5/Test#Hello> ), ( ?Random = 
            <http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#Bye> )]";
    String[] arr = str.split(",");
    String[] subArr = new String[arr.length];
    int j = 0;
    for (String i : arr) {
        subArr[j] = i.split("#", 2)[1].replaceAll("\\>|\\)|\\]", "");
        j++;
    }
    System.out.println(Arrays.toString(subArr));

Out put:

  [Hello , Bye ]

edited Sep 17, 2013 at 16:53

answered Sep 17, 2013 at 16:39

Ruchira Gayan Ranaweera

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Comments

Paul Vargas · Accepted Answer · 2013-09-17 19:18:56Z

0

Try the regular expression:

(?<=#)([^#>]+)

e.g.:

private static final Pattern REGEX_PATTERN = 
        Pattern.compile("(?<=#)([^#>]+)");

public static void main(String[] args) {
    String input = "[( ?A = <http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#Hello> ), ( ?A = <http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#World> )]";
    Matcher matcher = REGEX_PATTERN.matcher(input);
    while (matcher.find()) {
        System.out.println(matcher.group());
    }
}

Output:

Hello
World

answered Sep 17, 2013 at 19:18

Paul Vargas

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