For loops javascript

Question

Is there a way to set my for loop to hit all instances of string[i].length == length before decreasing the value of length by 1? I have messed around with adding while loops but I can't quiet get it.

This script is meant to order an array from greatest to least based on the length of each item. Only problem is I can't figure out how to order it without skipping array item lengths that have already been detected.

var string = ["hello", "world", "fishing", "before", "all", "test"];
var length = 0;
word = 0;
for (x = 0; x < string.length; x++) {
if (string[x].length > length) {
   var length = string[x].length;
   word = string[x];
}
}
string1 = [];
for (i = 0; i < string.length; i++) {
if (string[i].length == length) {
  length = string[i].length - 1;
  string1.push(string[i]);
  i = 0;
}
}
console.log(string1);

what is the result you desired?

Oki E. Rinaldi
– Oki E. Rinaldi

2013-10-29 03:11:39 +00:00
Commented Oct 29, 2013 at 3:11 — Oki E. Rinaldi
– Oki E. Rinaldi, Commented Oct 29, 2013 at 3:11

Arun P Johny · Accepted Answer · 2013-10-29 03:20:09Z

2

why not use Array.sort()

var string = ["hello", "world", "fishing", "before", "all", "test"];

string.sort(function(o1, o2){
    return o1.length - o2.length;
})

console.log(string)

Demo: Fiddle

Manual Sorting: Fiddle

edited Oct 29, 2013 at 3:20

answered Oct 29, 2013 at 3:13

Arun P Johny

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Comments

Jeff Storey · Accepted Answer · 2013-10-29 03:12:20Z

0

Why not use javascript's build in sort function http://www.w3schools.com/jsref/jsref_sort.asp

You can pass it a sortfunction - use that to compare the string's length and let javascript do the sorting for you.

answered Oct 29, 2013 at 3:12

Jeff Storey

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