How can I get python to get the contents of an HTTP page? So far all I have is the request and I have imported http.client.
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5 Answers
Using urllib.request is probably the easiest way to do this:
import urllib.request
f = urllib.request.urlopen("http://stackoverflow.com")
print(f.read())
4 Comments
BiscottiGummyBears
Tried that and I got "AttributeError: 'module' object has no attribute 'urlopen'"
Greg Hewgill
Sorry, I just noticed that you were using Python 3. I've updated my example to match.
Greg Hewgill
@Davide Gualano: The Python 2.x
urllib2 module has been rolled into the Python 3.x urllib set of modules: docs.python.org/library/urllib2.html
Davide Gualano
@Greg: my bad, I didn't read the question title carefully enough :)
Usage built-in module "http.client"
import http.client
connection = http.client.HTTPSConnection("api.bitbucket.org", timeout=2)
connection.request('GET', '/2.0/repositories')
response = connection.getresponse()
print('{} {} - a response on a GET request by using "http.client"'.format(response.status, response.reason))
content = response.read().decode('utf-8')
print(content[:100], '...')
Result:
200 OK - a response on a GET request by using "http.client" {"pagelen": 10, "values": [{"scm": "hg", "website": "", "has_wiki": true, "name": "tweakmsg", "links ...
Usage third-party library "requests"
response = requests.get("https://api.bitbucket.org/2.0/repositories")
print('{} {} - a response on a GET request by using "requests"'.format(response.status_code, response.reason))
content = response.content.decode('utf-8')
print(content[:100], '...')
Result:
200 OK - a response on a GET request by using "requests" {"pagelen": 10, "values": [{"scm": "hg", "website": "", "has_wiki": true, "name": "tweakmsg", "links ...
Usage built-in module "urllib.request"
response = urllib.request.urlopen("https://api.bitbucket.org/2.0/repositories")
print('{} {} - a response on a GET request by using "urllib.request"'.format(response.status, response.reason))
content = response.read().decode('utf-8')
print(content[:100], '...')
Result:
200 OK - a response on a GET request by using "urllib.request" {"pagelen": 10, "values": [{"scm": "hg", "website": "", "has_wiki": true, "name": "tweakmsg", "links ...
Notes:
- Python 3.4
- Result from the responses most likely will be differ only content
Comments
You can also use the requests library. I found this particularly useful because it was easier to retrieve and display the HTTP header.
import requests
source = 'http://www.pythonlearn.com/code/intro-short.txt'
r = requests.get(source)
print('Display actual page\n')
for line in r:
print (line.strip())
print('\nDisplay all headers\n')
print(r.headers)
1 Comment
Nam G VU
Is this Python 3?
pip install requests
import requests
r = requests.get('https://api.spotify.com/v1/search?type=artist&q=beyonce')
r.json()
Comments
Add this code which can format data for human reading:
text = f.read().decode('utf-8')
