I have the same problem like in this question:
How do I check if a string contains another string in Swift?
But now a few months later I wonder if it can be done without using NSString? I nice and simple contains-method would be fine. I searched the web and the documentation but I found nothing!
Same way, just with Swift syntax:
let string = "This is a test. This is only a test"
if string.rangeOfString("only") != nil {
println("yes")
}
For Swift 3.0
if str.range(of: "abc") != nil{
print("Got the string")
}
is, and if you print the range you will get something like 2..<4 {^_^} --> if let range = string.rangeOfString("is") { print(range) }
rangeOfString is an NSString method.String actually provides a "contains" function through StringProtocol.
No extension whatsoever needed:
let str = "asdf"
print(str.contains("sd") ? "yep" : "nope")
https://developer.apple.com/reference/swift/string
https://developer.apple.com/documentation/swift/stringprotocol
If you want to check if your string matches a specific pattern, I can recommend the NSHipster article about NSRegularExpressions: http://nshipster.com/nsregularexpression/
StringProtocol - so it also works for String.StringProtocol 👉 developer.apple.com/documentation/swift/stringprotocol/… it's more convenient and elegant way than range(of:)I wrote an extension on String for SWIFT 3.0 so that i could simply call absoluteString.contains(string: "/kredit/")
extension String {
public func contains(string: String)-> Bool {
return self.rangeOfString(string) != nil
}
}
just to demonstrate the use of options.
var string = "This is a test. This is only a test. Not an Exam"
if string.range(of:"ex") != nil {
print("yes")
}
if string.range(of:"ex", options: String.CompareOptions.caseInsensitive) != nil {
print("yes")
}
