I have something like this (Python3):
for p in something:
for r in something_else:
print(r, end=" ")
but I want each last print in the inner loop to end with a newline to create a nice table. Is there some short and elegant way to do it?
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1 Answer
Like this?
for p in something:
for r in something_else:
print("%s\t" % r, end=" ")
print()
More elegant might be
for p in something:
print(" ".join(map(str, something_else)))
Note that this will just print a table of the elements of something_else a bunch of times. What is in your list? How do you want the table to look? It might help if you're a little more specific in your question.
3 Comments
jonrsharpe
You can
map(str, something_else) if it doesn't just contain strings.Sakura
Well, I need no whitespace (except the newline) after the last item in the row. something_else is a list of ints. I just need: 1 2 3 4newline 3 4 5 6newline etc. something_else in in fact a p (I have made an error above) and it is a list of ints. I just now use: ` i = 0 for r in p: i += 1 if i < n: print(r, end=" ") else: print(r)` which looks ugly (sorry cannot format the code properly in the comment)
pdowling
" ".join(...) is what you are looking for - it places a space (" ") between each item in the passed list, and returns the resulting string. See my answer.