How to sort one array the same as another one?

Question

My problem: I have an array of objects which I sort ASC DESC by one of the objects keys, after that I need to sort an array of string that will be sorted the way the object array has been sort. example:

arrayOfObjects = [{name:"john",nuber:6,food:"pizza"},
               {name:"david",nuber:2,food:"gulash"},
               {name:"margaret",nuber:7,food:"gugi barries"}]

arrayOfStrings = ['r1','r2','r3']

so each object in arrayOfObjects has its own string. so say, john has r1, and they are both first indexed, when I sort by number john goes second, and I want hes number to go second as well (as well as david and margaret numbers)

I need to re-arrange the arrayOfStrings the same way (I dont care what it was sorted by) the arrayOfObjects was sorted

My sorting function :

dataArray.sort(dynamicSort(sortBy)); 
function dynamicSort(property) {
    var sortOrder = 1;
    if(property[0] === "-") {
        sortOrder = -1;
        property = property.substr(1);
    }
    return function (a,b) {
        if(direction=='asc'){
            var c = b;
            b=a;
            a=c;
        }
        var result = ( b[property] < a[property]) ? -1 : ( b[property]> a[property]) ? 1 : 0;
        return result * sortOrder;
    }
}

You could add a property to your objects that will be sorted, like {name:"john", r:'r1' ... and then retrieve these values when the array is sorted. — Hacketo
– Hacketo, Commented Jul 20, 2015 at 9:57

corazza · Accepted Answer · 2015-07-20 09:59:45Z

2

I suggest you zip the list in the format [[object, string], ...] and then sort according to the first element of the tuple. You can unzip the list afterwards.

answered Jul 20, 2015 at 9:59

corazza

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4 Comments

nadiTime Over a year ago

That is a good idea, I had a similar one, just to add each string to its original object, at the key:string and to read it from there. though I wanted to see if there is a way I can 'remember what the the sort changed'

corazza Over a year ago

@nadiTime No, I'm pretty sure there isn't, it's not practical at all. I mean at best you'd be doing the sorting work twice which is not something that you want. Just do it all in one go -- either way will do (your or mine), it's just a matter of whether it makes sense for the string to be a part of the object or not.

nadiTime Over a year ago

your absolutely right, I don't want to sort the array again. thanks

corazza Over a year ago

@nadiTime If that's it then, you can accept the answer :)

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