cmd to run exe not working from Python

Question

consider portion of Python code(Python 2.7) on Win 7 machine,

toolPath="C:\\Program Files (x86)\\Target Compiler Technologies\\adsp2-12R2\\bin\\WINbin"

This is executed from python script under

C:\dev\bin\toplevel\python

Now, I need to execute a command that runs(compiles and builds a DSP library, .prx is a project file for the library) as

C:\Program Files (x86)\Target Compiler Technologies\adsp2-12R2\bin\WINbin\chessmk.exe ".\..\..\..\dev\lib\adsp2\mylibs.prx -r -s

I am able to do that in cmd.exe shell as

%toolPath%\chessmk.exe "..\..\..\dev\lib\adsp2\mylibs.prx" -r -s

I can do the same in Python as

cmd = '"C:\\Program Files (x86)\\Target Compiler Technologies\\adsp2-12R2\\bin\\WINbin\\chessmk.exe" "C:\\SVN\\ASROmni\\trunk1\\\dev\\lib\\adsp2\\mylibs.prx" -r'
subprocess.check_output(cmd,stderr=subprocess.STDOUT,shell=False)

But, I have not been able to write similar code for Python, with relative paths and using toolpath variable. for example,

cmd = 'toolPath+"\\chessmk.exe" ".\\..\\..\\..\\dev\\lib\\adsp2\\mylibs.prx" -r -s'
subprocess.check_output(cmd,stderr=subprocess.STDOUT,shell=False)

gives error:

WindowsError: [Error 2] The system cannot find the file specified

following did not work too:

cmd = '"C:\\Program Files (x86)\\Target Compiler Technologies\\adsp2-12R2\\bin\\WINbin\\chessmk.exe" ".\\..\\..\\..\\dev\\lib\\adsp2\\mylibs.prx" -r'
subprocess.check_output(cmd,stderr=subprocess.STDOUT,shell=False)

Update: from one of the comments, I tried

cmd = os.path.join(toolPath,"chessmk.exe")+' C:\\SVN\\ASROmni\\trunk1\\\dev\\lib\\adsp2\\mylibs.prx -r'

it works,but the relative path one

cmd = os.path.join(toolPath,"chessmk.exe")+' .\\..\\..\\..\\dev\\lib\\adsp2\\mylibs.prx -r'

still dosn't.

any help.( This is my first day with python, so bear with me)
please note that the cmd should be run from within Python, not invoking shell=True.
Thanks
sedy

martineau · Accepted Answer · 2015-08-22 01:06:01Z

1

It may be how you're passing the arguments to check_output(), try this instead:

toolPath = ('"C:\\Program Files (x86)\\Target Compiler Technologies\\'
            'adsp2-12R2\\bin\\WINbin\\chessmk.exe"')

cmd = [toolPath, '"..\..\..\dev\lib\adsp2\mylibs.prx"', '-r' '-s']

subprocess.check_output(cmd, stderr=subprocess.STDOUT, shell=False)

However the relative path for the location of mylibs.prx may still be a problem. You might be able to make it work by calling os.chdir() right before calling check_output().

edited Aug 22, 2015 at 1:06

answered Aug 22, 2015 at 0:15

martineau

124k29 gold badges181 silver badges319 bronze badges

Sign up to request clarification or add additional context in comments.

6 Comments

user915783 Over a year ago

Hi Martineau, well %toolpath% was used as I could only create environment variables in shell. here,In python, toolpath is an ordinary variable, so, does it still need os.environ?

martineau Over a year ago

Using a relative path is making assumption about the current working directory. You can either change the cwd appropriately using os.chdir() before calling check_output() or pass the argument with an absolute path.

user915783 Over a year ago

Hi martineau, my bad, I was using extra // for relative path, so that is why it did not work. Now, It works. Thanks. One small query though, can i direct op of execution to STDOUT if not an error?

martineau Over a year ago

That good to hear. You don't need to do anything for it to go to stdout (that's the default).

user915783 Over a year ago

I checked and the subprocess.check output only directs child process stdout to stderror, but when not in error, i should be able to see the message from child process(here, the DSP library that is executed)on sucess too, which i don't see .

|

Collectives™ on Stack Overflow

cmd to run exe not working from Python

1 Answer 1

6 Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

6 Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related