preg_replace equivalent in java

Question

How to convert this code into java code

$response = preg_replace('/[\x00-\x1F\x80-\xFF]/', '', $response);

I try this

String jsonStr = "Some Json string";
jsonStr.replaceAll("/[\x00-\x1F\x80-\xFF]/", "");

But it show an error

Invalid escape sequence (valid ones are  \b  \t  \n  \f  \r  \"  \'  \\ )

Check this: stackoverflow.com/a/60830223/6533853

Ninja
– Ninja

2020-03-24 11:34:36 +00:00
Commented Mar 24, 2020 at 11:34 — Ninja
– Ninja, Commented Mar 24, 2020 at 11:34

stevecross · Accepted Answer · 2015-08-24 10:16:35Z

1

You have to escape the backslashes with another backslash like this:

jsonStr.replaceAll("[\\x00-\\x1F\\x80-\\xFF]", "");

Backslashes in strings introduce special characters in Java.

edited Aug 24, 2015 at 10:16

answered Aug 24, 2015 at 9:28

stevecross

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2 Comments

Nur Uddin Over a year ago

I am getting a json string from a website. json string contains ` ï»¿` in start point. Now I how I remove this. I try with this code in php and it works for me. but I cant do it in android. can you please give any advice?

stevecross Over a year ago

In Java you don't need a delimiter for the regex. Thus removing the slashes should give you the same result as in PHP. I updated the answer.

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