I get the following JSON:
[
{
"user_id": "someValue"
}
]
It's saved inside a String.
I would like to convert it to a JSONObject which fails (as the constructor assumes a JSON to start with {). As this doesn't seem to be possible I'd like to convert it to a JSONArray. How can I do that with SimpleJson?
JSONParser parser = new JSONParser();
JSONArray array = (JSONArray)parser.parse("[{\"user_id\": 1}]");
System.out.println(((JSONObject)array.get(0)).get("user_id"));
You need to cast to a JSONArray as that is what the string contains.
For your task you could use code as bellow:
String t = "[{\"user_id\": \"someValue\"}]";
JSONParser parser = new JSONParser();
JSONArray obj = (JSONArray) parser.parse(t);
System.out.println(obj.get(0));
And result would be JSONObject.
String actualJsonObject = // assuming that this variable contains actual object what ever u want to pass as per your question says
JSONParser parser = new JSONParser();
JSONArray userdataArray= (JSONArray) parser.parse(actualJsonObject );
if(userdataArray.size()>0){
for (Object user : userdataArray) {
JSONObject jsonrow=(JSONObject)parser.parse(String.valueOf(user));
String User_Id= (String)jsonrow.get("user_Id"); \\ Each User_Id will be displayed.
} else{
System.out.println("Empty Array....");
}
It works for me.
String jsonString = "[{\"user_id\": \"someValue\"}]";
JSONArray jsonArray = new JSONArray();
JSONParser parser = new JSONParser();
try {
jsonArray = (JSONArray) parser.parse(js);
} catch (ParseException e) {
e.printStackTrace();
}