I have a component in my c# application that provide strings like these:
"2004/1/11"
"2015/12/10"
"1998/1/2"
But i want to change them to these formats:
"2004/01/11"
"2015/12/10"
"1998/01/02"
Any idea?
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no...component is used in all part of application and i just have to change output....i want to change output string to new format that i wantsaeed– saeed2016-05-06 09:51:35 +00:00Commented May 6, 2016 at 9:51
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5 Answers
It seems that the strings in the question are actually dates, in that case DateTime class is what you're looking for:
String source = "2015/12/10";
String result = DateTime
.ParseExact(source, "yyyy/M/d", CultureInfo.InvariantCulture)
.ToString("yyyy/MM/dd", CultureInfo.InvariantCulture);
In case the strings are not dates (say, some weird codes which look like dates) and you want just insert zeroes:
String source = "2015/12/10";
String result = Regex
.Replace(source, "(?<=/)[0-9](?![0-9])", match => "0" + match.Value);
Comments
Try :
string InputStr = "2004/1/11";
String OutputStr = String.Format("{0:yyyy/MM/dd}", Convert.ToDateTime(InputStr));
Comments
If you do not want to convert the strings to dates and back, you could use the Regex.Replace-method. The code could look a little something like this:
myString = Regex.Replace(myString,@"[^\d](\d)(?=(/|$))","/0$1");
EDIT: Corrected the pattern.
1 Comment
Dmitrii Bychenko
Counter example:
myString = "2015/12/1";; the output is 2015/012/01 when 2015/12/01 expectedThis might help you out with your question: https://msdn.microsoft.com/en-us/library/8kb3ddd4(v=vs.110).aspx
Maybe a timeformat setting will solve your problem.
Comments
its date so you can convert it this way
string str = "2004/1/11";
DateTime dt = DateTime.ParseExact(str, "yyyy/M/dd", CultureInfo.InvariantCulture);
string newstr = dt.ToString("yyyy/MM/dd", CultureInfo.InvariantCulture)
2 Comments
Dmitrii Bychenko
Do not omit
CultureInfo.InvariantCulture in the .ToString() or you can have, say, 2004.01.11 (notice dots) since current culture will be used - Russian in the output aboveDmitrii Bychenko
when parsing exact
"yyyy/M/d" (please, notice one d only) is a better pattern than "yyyy/M/dd" in a view of "1998/1/2" input which will throw a format exception.