Wrap std::vector of std::vectors, C++ SWIG Python

Question

I want to wrap a C++ vector of vectors to Python code by using SWIG.

Is it possible to wrap this type of vector of vectors?

std::vector<std::vector<MyClass*>>;

In the interface file MyApplication.i I added these lines:

%include "std_vector.i"
%{ 
#include <vector> 
%} 

namespace std {
   %template(VectorOfStructVector) vector<vector<MyClass*>>;
}

But, I'm getting an Error when SWIG is executed. I'm able to wrap this type (using reference to the vector):

 std::vector<std::vector<MyClass*>*>;

But, it's not working properly, I cannot access the items. That's why I'm interested in this type (without the reference):

 std::vector<std::vector<MyClass*>>;

Any ideas?

If this really is C++ and not C++0x, please make sure you include a space between the closing angle brackets. eg >> should be > > — John Dibling
– John Dibling, Commented Sep 21, 2010 at 15:47

Charles Beattie · Accepted Answer · 2010-09-21 15:47:23Z

4

Is it a C++ parsing issue?

 std::vector<std::vector<MyClass*> >;
 ---Important space---------------^

answered Sep 21, 2010 at 15:47

Charles Beattie

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2 Comments

Also this line was needed in the interface file: %template(VectorOfStructVector) vector<vector<MyClass*> >;

@Javier, another solution is to compile with "--std=c++0x" if you're using gcc. C++0x has fixed this problem.