variadic constructor inheritance

Question

template<typename Type, size_t Dimensions> 
struct Base 
{  
     template <typename ... Args>
    Base (const Args& ... args) : /*initialize*/ {}
/*
some functionality
*/
};

template<size_t Dimensions>
using myBase = typename Base<_DOUBLE,Dimensions> ;

template<size_t Dimensions> 
class Derived: public myBase<Dimensions> 
{
/*
some additional functionality
*/
}

myBase<2> mB(1.0,2.0); //works
Derived<2> D(1.0,2.0); //error C2661: 'Derived<2>::Derived': no overloaded function takes 2 arguments

Why the implicit inheritance of the constructor doesn't work and if it is necessary, how to create the correct constructor in this case?

O'Neil · Accepted Answer · 2016-06-24 02:50:01Z

3

No need of typename here:

using myBase = typename Base<_DOUBLE,Dimensions> ;

Constructors are not inherited unless explicitely specified with using keyword (see Inheriting constructors).

template<size_t Dimensions> 
class Derived: public myBase<Dimensions> 
{
public:
    using myBase<Dimensions>::myBase;
};

answered Jun 24, 2016 at 2:50

O'Neil

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