array_push won't give an array, prints out integer value [duplicate]

Question

I'm doing a very simple php program with array_push, but it isn't working according to the documentation. Every time i try to print the value of the final array, it gives me an integer. Could someone please help me with this?

Here's my code:

<?php
    $preArray = array('1','2','3','4','5','6','7','8');
    $val = 10;
    $array = array_push($preArray, $val);

    print_r($array);
?>

This is what it outputs:

Tristan · Accepted Answer · 2016-07-03 21:07:27Z

6

array_push() returns the new number of elements in the array. So if you're not interested in the number of elements in the array then just use:

array_push($preArray, $val);

The variable $preArray will contain the value pushed into it.

print_r($preArray);

edited Jul 3, 2016 at 21:07

answered Jul 3, 2016 at 21:05

Tristan

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2 Comments

user557846 Over a year ago

most of us would just do: $preArray[]=$val

gavgrif Over a year ago

@Dagon - not me - i push values into arrays using array_push() :))

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