how to get first and last element from array

Question

guys i am storing dates like these 07/01/2016, 07/02/2016, 07/03/2016, 07/04/2016 in db and when i fetch these dates from db using mysql_fetch_array() the result is the whole array now i want to get only the starting and ending date i.e 07/01/2016 and 07/04/2016...i tried using explode function but explode function breaks a string into an array...and i am unable to find a String To Array function in php...Kindly help me and tell me what should i do...

   $leave_dates=$_POST['dates'];
   $check_dates=explode(',', $leave_dates);
    foreach ($check_dates as $date)
{
    # code...
    $count_dates=count($date);
    //THIS GIVES THE COUNT OF DATES E.G 4
    NOW I WANT TO ACCESS THE FIRST AND THE LAST ELEMENT


}

Will this work for first $check_dates[0] and for last $check_dates[count($check_dates)-1] and also check by isset first — Niklesh Raut
– Niklesh Raut, Commented Jul 26, 2016 at 8:54
First = $check_dates[0]; $last= $check_dates[count($check_dates)-1]; — user2417483
– user2417483, Commented Jul 26, 2016 at 8:55
For first element: $check_dates[0] and for last: $check_dates[(sizeof($check_dates)-1)] — Akshay
– Akshay, Commented Jul 26, 2016 at 8:58

muffe · Accepted Answer · 2016-07-26 08:55:51Z

2

You could use reset and end

$firstDate = reset($check_dates);
$lastDate = end($check_dates);

answered Jul 26, 2016 at 8:55

muffe

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Comments

Passionate Coder · Accepted Answer · 2016-07-26 08:58:05Z

0

You can try this

<?php
$row = array('07/01/2016','07/02/2016','07/03/2016','07/04/2016');
$total = count($row);
echo $row[0];
echo "<br>";
echo $row[$total-1];

output

07/01/2016
07/04/2016

answered Jul 26, 2016 at 8:58

Passionate Coder

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Comments

Janani Kumar · Accepted Answer · 2016-07-26 08:58:23Z

0

you can also use array_shift and array_pop

$first_element = array_shift($check_dates);
$last_element = array_pop($check_dates);

answered Jul 26, 2016 at 8:58

Janani Kumar

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Comments

Muhammad Awais · Accepted Answer · 2016-07-26 08:58:30Z

0

try this

$firstDate = current($count_dates);
$lastDate = end($count_dates);

answered Jul 26, 2016 at 8:58

Muhammad Awais

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2 Comments

Farside Over a year ago

can you please expand you answer, and elaborate a bit on the solution?

Muhammad Awais Over a year ago

current() and end() both are build pointer for the array in php. you can check the details php.net/manual/en/function.current.php php.net/manual/en/function.end.php

Bhavin · Accepted Answer · 2016-07-26 08:59:48Z

0

Best way is to work out on Queries.

select * from table_name
where id = (select id from tab1 order by col1 asc limit 1) or
id = (select id from tab1 order by col1 desc  limit 1);

answered Jul 26, 2016 at 8:59

Bhavin

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Comments

Keyur Chavda-kc1994 · Accepted Answer · 2016-07-26 09:04:36Z

0

try this ,

<?php 

    $check_dates=array('2016-5-11','2016-8-4','2016-4-9');
    $firstDate = current($check_dates);
    $lastDate = end($check_dates);

    print_r($firstDate);
    print_r($lastDate);

?>

Output will be :

 2016-5-11
 2016-4-9

answered Jul 26, 2016 at 9:04

Keyur Chavda-kc1994

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Comments

Farside · Accepted Answer · 2016-07-26 10:11:50Z

0

here's the potential solution:

$leave_dates=$_POST['dates'];
$check_dates=explode(',', $leave_dates);
//To obtain the first element
$first_element=$check_dates[0];
//To obtain the last element
$last_element=$check_dates[count($check_dates)-1];

edited Jul 26, 2016 at 10:11

Farside

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answered Jul 26, 2016 at 8:57

Sanghita

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Comments

Ashickur Rahman · Accepted Answer · 2016-07-26 11:11:46Z

0

Since you store all the value in an array named $check_dates. You can access the first element of an array with index 0

$firstlement=$check_dates['0'];

To access the last element of an array, you can use end function.

$lastement=end($check_dates);

edited Jul 26, 2016 at 11:11

answered Jul 26, 2016 at 9:12

Ashickur Rahman

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1 Comment

Farside Over a year ago

it could be a comment, it's not a full-fledged answer. Please read the best practices: stackoverflow.com/help/how-to-answer

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