can't find element by xpath using selenium

Question

I try this xpath but I don't know how to continue ? i have 2 objects in popup menu and i want to select the first one

the html of the page is:

</div>
<input class="sprite form-enter" type="submit" value="" name="wobi">
</div>
<div class="container">
<img src="/_media/home/img/icons/pension.png">
<div class="login-text-container">
<a class="sprite form-enter" href="https://pension.wobi.co.il/login" value="" name="pension" type="submit"></a>
</div>
</div>

the java code is:

driver.findElement(By.xpath("//input[@class='sprite form-enter' and input//@name='wobi']")).click();
Thread.sleep(2000);

After execution of code I got the following exception:

Exception in thread "main" org.openqa.selenium.NoSuchElementException: no such element: Unable to locate element: {"method":"xpath","selector":"//input[@class='sprite form-enter' and input/@name='wobi']"}

What's wrong in my code?

Do you mean you have two element with the same class sprite form-enter and name wobi?? — Saurabh Gaur
– Saurabh Gaur, Commented Aug 23, 2016 at 13:20
your XPath is wrong better try and check if it works in Firebug / Firepath — Mrunal Gosar
– Mrunal Gosar, Commented Aug 23, 2016 at 13:24

Saurabh Gaur · Accepted Answer · 2016-08-23 13:29:47Z

1

Actually you are try with wrong xpath, the correct xpath would be :-

//input[@class='sprite form-enter' and @name='wobi']

But I would suggest you, try using By.cssSelector() here because it would be much faster than xpath as below :-

driver.findElement(By.cssSelector("input.sprite.form-enter[name = 'wobi']")).click();

answered Aug 23, 2016 at 13:29

Saurabh Gaur

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Comments

lauda · Accepted Answer · 2016-08-23 12:55:15Z

0

Try this selector:

//input[@class='sprite form-enter'][@name='wobi']

answered Aug 23, 2016 at 12:55

lauda

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Siva · Accepted Answer · 2016-08-23 13:25:17Z

0

Seems like you have a compound class, try using CSSSelector

driver.findElement(By.cssSelector(".sprite.form-enter")).click();

answered Aug 23, 2016 at 13:25

Siva

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