Get timestamp in seconds from python's datetime

Question

How to get timestamp from the structure datetime? What is right alternative for non-existing datetime.utcnow().timestamp()?

This answer below is much simpler than the accepted: stackoverflow.com/a/56689007/3559330 — mattyb
– mattyb, Commented May 21, 2021 at 23:20

Alex · Accepted Answer · 2020-05-23 12:35:40Z

70

use time, and int to remove the milliseconds

from time import time 

int(time())

# 1561043225

edited May 23, 2020 at 12:35

answered Jun 20, 2019 at 15:11

Alex

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galaxyan · Accepted Answer · 2016-09-02 14:06:03Z

13

import time,datetime
time.mktime(datetime.datetime.today().timetuple())

answered Sep 2, 2016 at 14:06

galaxyan

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kyb Over a year ago

Very cumbersome solution. As python. Many operations for such small work. C has time() and it works like a charm :)

Community · Accepted Answer · 2017-05-23 10:30:31Z

10

There is another stupid trick - achieve timedelta

(datetime.utcnow()-datetime(1970,1,1,0,0,0)).total_seconds()

found here. Better

(datetime.utcnow()-datetime.fromtimestamp(0)).total_seconds()

And this solution contains subseconds.

edited May 23, 2017 at 10:30

CommunityBot

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answered Sep 2, 2016 at 15:43

kyb

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Damotorie · Accepted Answer · 2016-09-02 14:32:29Z

9

If you don't have to get timestamp from structure datetime, you can decrease instruction like this

import time
print time.time()

answered Sep 2, 2016 at 14:32

Damotorie

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Prisacari Dmitrii Over a year ago

This construction returns the time in seconds since the epoch as a floating point number, for example: 1558442772.1057804.

Konchshell · Accepted Answer · 2016-09-02 15:45:38Z

-3

If I understand correctly what sort of output you are seeking:

from datetime import datetime
timestamp = datetime.now().strftime("%H:%M:%S")
print(timestamp)

> 11:44:40

EDIT: Appears I misinterpreted your question? You are asking for the naive universal time, then galaxyan's answer is concise.

answered Sep 2, 2016 at 15:45

Konchshell

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