Sorting object attributes in different orders

Question

I'm writing a soccer league program and I want to sort the table before printing it out. Each team is a member of a class with certain attributes and so far I've been able to sort the integer attributes correctly.

for team in sorted(teams, key=attrgetter("points", "goalDiff", "scored", "name"), reverse = True):

I want all the attributes except name to be reversed, is there a possible way to "un-reverse" the name attribute in this line of code or do I have to take on a different approach?

Are the other values numbers?

Martijn Pieters
– Martijn Pieters

2016-10-05 13:53:02 +00:00
Commented Oct 5, 2016 at 13:53 — Martijn Pieters
– Martijn Pieters, Commented Oct 5, 2016 at 13:53
Yes, all attributes except "name" are integers.

bullbo
– bullbo

2016-10-05 13:53:45 +00:00
Commented Oct 5, 2016 at 13:53 — bullbo
– bullbo, Commented Oct 5, 2016 at 13:53

Dimitris Fasarakis Hilliard · Accepted Answer · 2016-10-05 14:22:49Z

6

If all attributes (except the name) are numeric, negate those numbers to get a reverse sort for those:

sorted(teams, key=lambda t: (-t.points, -t.goalDiff, -t.scored, t.name))

Negating numbers gives you a way to reverse their sort order without actually having to reverse the sort.

If that's not the case, then you'd have to sort twice, first just by the name attribute (in forward order), then in reverse order by the other attributes. For any object where points, goalDiff and scored are equal, the original sorting order (by name) is retained, because the sort algorithm Python uses is stable:

sorted(
    sorted(teams,  key=attrgetter('name')),
    key=attrgetter("points", "goalDiff", "scored"),
    reverse=True)

edited Oct 5, 2016 at 14:22

Dimitris Fasarakis Hilliard

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answered Oct 5, 2016 at 13:53

Martijn Pieters

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