$myAry = array();
// I want to return the array's name.
// something like
echo $myAry.name;
// Should print "$myAry".
Thanks,
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dude learn the basic of php first or see some tutorial(s)Beginner– Beginner2016-12-27 06:43:49 +00:00Commented Dec 27, 2016 at 6:43
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What an arrogant comment when one doesn't even know what the person is doing !SpaceCorp– SpaceCorp2016-12-28 08:12:41 +00:00Commented Dec 28, 2016 at 8:12
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This post solved my issue : stackoverflow.com/questions/255312/…SpaceCorp– SpaceCorp2016-12-28 08:33:00 +00:00Commented Dec 28, 2016 at 8:33
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3 Answers
But if you type $myAry you already know the name of the variable. What is
it you are trying to achieve?
If you absolutely must know the identity of your variables...
function my_function ($my_array) {
$caller_info = array_shift(debug_backtrace());
$lines = file($caller_info['file']);
$line = $lines[$caller_info['line'] - 1];
if(preg_match('/my_function\\s*\\(\$(\\w+)/', $line, $matches)) {
$name_of_my_array = $matches[1];
echo $name_of_my_array;
}
}
Is this what you want?
1 Comment
SpaceCorp
Thank you, this is close, but it returns only the my_function's arg name(e.g. $my_array) every time, no matter what array is passed, and not what the arg is referring to. Example: if I use it like this my_function($new_name) It should return a string "$new_name" not "$my_array" as it does every time.
$array = array('name12'); $comma_separated = implode(",", $array);
echo $comma_separated; // name12
// Empty string when using an empty array:
var_dump(implode('hello', array())); // string(0) ""
1 Comment
SpaceCorp
Not looking for elements.
You can get argument name like this:
function get_function ($my_array) {
$f = new ReflectionFunction($my_array);
$result = array();
foreach ($f->getParameters() as $param) {
$result[] = $param->name;
}
return $result;
}
function sayHello($helloWorlds){
echo $helloWorld;
}
print_r(get_function('sayHello'));;
//Output
Array ( [0] => helloWorlds )
