How to split >1digit integers list and create a list from that digits? Python

Question

Say I have list a = [23, 2]. I need to split every element in list and then combine them to one list. So result be like a = [2, 3, 2] What I have for now is:

list = [int(i) for i in str(map([], map(lambda x: x*2, list(reversed(numlist))[1::2])))]

Where map(lambda x: x*2, list(reversed(numlist))[1::2]))) is the list of even indexed numbers (2, 4, 6...) each multiplied by 2.

It gives me: ValueError: invalid literal for int() with base 10: '<' on this line.

obviously you are passing an invalid list... please give a minimal reproducible example. — Julien
– Julien, Commented Mar 20, 2017 at 0:08

Stefan Pochmann · Accepted Answer · 2017-03-20 00:14:35Z

3

>>> map(int, ''.join(map(str, a)))
[2, 3, 2]

answered Mar 20, 2017 at 0:14

Stefan Pochmann

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Comments

moth · Accepted Answer · 2017-03-20 00:18:19Z

1

You can first change list to string then change this string back to integer list. Here is an example.

a = [23, 2]
a = [int(j) for j in ''.join([str(i) for i in a])]
print(a)

answered Mar 20, 2017 at 0:18

moth

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Comments

bits · Accepted Answer · 2017-03-20 00:30:01Z

1

Using two level List Comprehension:

a = [23, 2]
digits = [ int(x) for num in a for x in str(num) ]

edited Mar 20, 2017 at 0:30

answered Mar 20, 2017 at 0:15

bits

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1 Comment

juanpa.arrivillaga Over a year ago

list(str(num)) is unnecessary. Just use str(num) you can iterate directly over strings...

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