catching error breaks for loop in javascript?

Question

    for (var i = 0, len = IDs.length; i < len; i++) {

    entry = IDs[i];
    isAnyFailure = false;

    try{
    var id = db.getSiblingDB("door").jhi_user.findOne({"_id" : entry});
    } catch (err){

     failedIDs.push(entry);
     failedCount++;
     isAnyFailure = true;
    }

...
}

if it catches any error, it will continue to code or it will go to next iteration?

why don't you log your code, or step through in a debugger and see? — Matt Way
– Matt Way, Commented Apr 6, 2017 at 6:48

Shakti Phartiyal · Accepted Answer · 2017-04-06 07:00:26Z

2

The loop continues in try and catch:

    for (var i = 0; i < 10; i++)
    {
      try
      {
        if(i == 6)
        {
          document.getElementById('noid').html("x"); //this will cause an exception as no such ID exists
        }
        console.log("In try Iteration :: "+i);
      }
      catch (err)
      {
        console.log("In catch Iteration :: "+i);
      }
    }

The whole concept of try and catch is to continue the execution if an exception occurs rather than abruptly stopping the program / script.

edited Apr 6, 2017 at 7:00

answered Apr 6, 2017 at 6:50

Shakti Phartiyal

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