TypeError: 'float' object cannot be interpreted as an integer 4

Question

I'm trying to create sudoku, but I'm getting this error. I think it's because of the range line; maybe I'm doing it wrong, but range(int(numb/numb+3)) doesn't really work either. Thanks for the help.

File "D:\Games\Python\sudokuV2Test2.py", line 83, in estDansSousMatrice
    for i in range(bl, bl+3):
TypeError: 'float' object cannot be interpreted as an integer"

This is the code:

def estDansSousMatrice(grille,l,c,v):
    bc=(c/3)*3
    bl=(l/3)*3

    for i in range(bl, bl+3):
        for j in range(bc,bc+3):
            if grille[i][j]==v:
                return True
    return False

chris.acampos · Accepted Answer · 2017-05-18 02:44:03Z

1

Since your previously dividing bc and bl and then multiplying by 3, say we input c = 3 and l = 3 the outcomes for both of those would be 3.0 instead do for i in range(int(bl),int(bl)+3): and for j in range(int(bc),int(bc)+3):

answered May 18, 2017 at 2:44

chris.acampos

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1 Comment

Henrique Over a year ago

Thank you so much for the help.

Arya McCarthy · Accepted Answer · 2017-05-18 04:44:14Z

0

To be clear, you can sidestep the converting back to int by never making them floats in the first place. The // operator performs integer division, truncating the result. This lets you keep almost all of your original code.

def estDansSousMatrice(grille,l,c,v):
    bc=(c//3)*3  # Different
    bl=(l//3)*3  # Different

    for i in range(bl, bl+3):
        for j in range(bc,bc+3):
            if grille[i][j]==v:
                return True
    return False

answered May 18, 2017 at 4:44

Arya McCarthy

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