how to use while loop without infinite loop(python 2.7)

Question

I have been trying to create a program with python 2.7. This program creates a random number. (nlist[r] is saved in list[])

If list[0] is 'do' or 'ge' or 'gi', just print list and the program is ended.

If list[0] is 'mo' or 'yu', the while loop starts.

When list[k]=='yu' or 'mo', the loop must stop, print list, and also end the program. But this ended up in an infinite while loop...

Here is my code:

nlist=['do','ge','gi','yu','mo']
list=[]
def playYut():
    import random
    r=random.randrange(0,5)
    list.append(nlist[r])

playYut()

if list[0]=='do' or list[0]=='gae' or list[0]=='girl':
    for i in list:
        print i
else:
    k=0
    while list[k]:
        if list[k]=='yut' or list[k]=='mo':
            playYut()
            for i in list:
                print i
        else:
            for i in list:
                print i

you are not incrementing k ?

Priyesh Kumar
– Priyesh Kumar

2017-05-29 18:50:09 +00:00
Commented May 29, 2017 at 18:50 — Priyesh Kumar
– Priyesh Kumar, Commented May 29, 2017 at 18:50

void · Accepted Answer · 2017-05-29 21:10:44Z

1

I've made a few changes in your code which i will be explaining below.

import random
nlist=['do','ge','gi','yu','mo']
check_list = ['do','ge','gi']
loop_check_list = ['yu' ,'mo' ]
flag =1
your_list=[]
k=0
def playYut():
    r=random.randrange(0,5)
    your_list.append(nlist[r])
playYut()

if your_list[0] in check_list:
    print list1

elif your_list[0] in loop_check_list:
    while flag==1:
        k+=1
        playYut()
        if your_list[k] in loop_check_list:
            print your_list
            flag=0

1) Let import statements be declared at the top of the program it's good practice. Check this out for a detail explanation.

In Python, what happens when you import inside of a function?

2) Instead of this

if your_list[0]=='do' or your_list[0]=='gae' or your_list[0]=='girl':

this is more elegant to look at.

if your_list[0] in some_list_with_those_values:

3) Also instead of naming a list as list define some variable name for it. For ex your_list.

4) Also you can use either break or a flag variable but i prefer using flag variable here. Understanding them is essential. Set a flag variable with a value say 1 and change it to 0 when the condition is changed. This way you can exit out of the while loop.

5) I don't clearly understand what you want to do with your program. But from your description this a working code that you might want.

edited May 29, 2017 at 21:10

answered May 29, 2017 at 19:15

void

2,6622 gold badges23 silver badges35 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

MooingRawr Over a year ago

your statement 2 is a bit misleading. OP's statement is perfectly fine. Also if you are going to give an answer please point out that list is a bad variable name to use instead of just changing it to list1

void Over a year ago

@MooingRawr thanks for pointing it out man. Got confused a bit!!. :)

Yevhen Kuzmovych · Accepted Answer · 2017-05-29 19:21:44Z

1

It is a very common mistake you did there, my friend. You have to change the value of k for looping or add a break statement for stoping the loop.

edited May 29, 2017 at 19:21

Yevhen Kuzmovych

12.3k8 gold badges32 silver badges54 bronze badges

answered May 29, 2017 at 18:44

PyManiac

5044 silver badges12 bronze badges

Comments

Breno Baiardi · Accepted Answer · 2017-05-29 19:32:23Z

0

You need to increase the value of k in every loop you can do so by adding

K+=1

or

k=k+1

answered May 29, 2017 at 19:32

Breno Baiardi

1091 silver badge16 bronze badges

Collectives™ on Stack Overflow

how to use while loop without infinite loop(python 2.7)

3 Answers 3

2 Comments

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

2 Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related