I have few arrays in my script
a=(1 2 3)
b=(3 4 5)
User inputs which list he wants to print out.
./array.sh a
How do I print the elements of array?
I have tried doing the following and couldn't print
array=$1
echo ${!array[@]}
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What is your bash version?anubhava– anubhava2017-07-13 21:51:58 +00:00Commented Jul 13, 2017 at 21:51
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GNU bash, version 4.3.11(1)-release (x86_64-pc-linux-gnu)pdna– pdna2017-07-13 21:52:39 +00:00Commented Jul 13, 2017 at 21:52
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2 Answers
You can use declare -n for named reference of your variables like this:
a=(1 2 3)
b=(3 4 5)
declare -n arr="${1?need an array name}"
printf "%s\n" "${arr[@]}"
Then execute it as:
./array.sh a
1
2
3
./array.sh b
3
4
5
1 Comment
pdna
declare -n array=$1 works fine. thanksMake the [@] part of your indirection:
a=(1 2 3)
myfunction() {
array="$1[@]"
echo "${!array}"
}
myfunction a
2 Comments
pdna
I have so many arrays in my script. So
set -- a may not scale well in my case :) But I get the logic behind your commands. Thanks.
that other guy
@pdna This is just how you set
$1 from within the script to make it self-contained and runnable. It's easier to copy-paste and reproduce than having to create a script and run it with certain parameters. I changed it to set it via a function instead