Rails Simple_form_for hidden_field Value Incorrect

Question

I have the following form in my Rails app:

   <%= simple_form_for(@ingredient) do |f| %>
      <%= f.error_notification %>

      <div class="form-inputs">
        ...
        <%= f.hidden_field :recipe, value: @recipe.id %>
      </div>

      <div class="form-actions text-center">
        <%= f.button :submit %>
      </div>
    <% end %>

I have this in my controller:

@recipe = Recipe.find(params[:id])
@ingredient = Ingredient.new
@ingredients = Ingredient.where(user_id: current_user.id, recipe_id: @recipe.id)

And I have tested with byebug that @recipe.id comes out as a number (4 in the instance I am testing).

When the form actually gets rendered, the value is correct:

However, when the record is create the ingredient still is created with a recipe_id of nil. Any wisdom as to what's going wrong?

you are looking at the wrong hidden field. yours is inside the .form-inputs div, just below that selected hidden input — MrYoshiji
– MrYoshiji, Commented Aug 17, 2017 at 18:59
@MrYoshiji that is correct and the OP has been updated. Unfortunately, that makes the problem even more vexing! — Liz
– Liz, Commented Aug 17, 2017 at 19:04
the f.hidden_field :recipe should be f.hidden_field :recipe_id — MrYoshiji
– MrYoshiji, Commented Aug 17, 2017 at 19:05
@MrYoshiji YES! Thank you. If you write up an answer I'll happily accept it! — Liz
– Liz, Commented Aug 17, 2017 at 19:06

MrYoshiji · Accepted Answer · 2017-08-17 19:19:04Z

1

The f.hidden_field :recipe should be f.hidden_field :recipe_id

answered Aug 17, 2017 at 19:19

MrYoshiji

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Comments

Pedro Gabriel Lima · Accepted Answer · 2017-08-17 19:16:51Z

0

As already answered, you should use f.hidden_field :recipe_id

But I will add a plus, try use like this:

Ingredient controller:

@ingredient = Ingredient.new({:recipe_id => @recipe.id})

In ingredient view:

f.hidden_field :recipe_id

In this way you don't need instantiate recipe in view. This will work for your edit view too! It keep things clear!

edited Aug 17, 2017 at 19:16

answered Aug 17, 2017 at 19:04

Pedro Gabriel Lima

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1 Comment

Liz Over a year ago

Thank you for the answer. However, after updating the OP with the correct form-input, the error persists (where the ingredient is created with the recipe_id of nil) even with the html listing a value of 4.

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