list1=[1, 2, 3, 4, 5]
I want to create a list [[1, 2, 3, 4, 5]] from list1.
I tried list(list1) but it's showing only [1, 2, 3, 4, 5] instead of [[1, 2, 3, 4, 5]].
5 Answers
Just initialise a new list which has a sub-list that is list1.
This is done with:
[list1]
which will give:
[[1, 2, 3, 4, 5]]
Or alternatively, when you are defining list1, you can define it already nested inside another list:
list1 = [[1, 2, 3, 4, 5]]
Note that when you were trying to nest the original list inside another list, using list() will not work.
If you read the documentation:
The constructor builds a list whose items are the same and in the same order as iterable’s items. iterable may be either a sequence, a container that supports iteration, or an iterator object. If iterable is already a list, a copy is made and returned, similar to iterable[:]. For example, list('abc') returns ['a', 'b', 'c'] and list( (1, 2, 3) ) returns [1, 2, 3]. If no argument is given, the constructor creates a new empty list, [].
The key thing mentioned here is that list creates a list from an iterable. As list1 is a list already, it is an iterable. This means that the list() constructor will treat as an iterable and create a new list from the elements inside list1 - creating a copy of it. So that is why it wasn't working as you expected it to.
Comments
Have you tried?
list2 = [list1]
Comments
You'll have to put it in another list using. When you declare a list, you put them in two square brackets. If you want to make a list of lists, you'll have to use them twice.
lis = [your_list]
1 Comment
Ghilas BELHADJ
list() is redundantThis works for me
list1=list([list1])
Comments
One line solution :
list1=[1, 2, 3, 4, 5]
print([[nested_list for nested_list in list1]])
or just use:
list1=[1, 2, 3, 4, 5]
nested_list=[list1]
arraysif you're talking aboutlists.list([list1])does it for me.[list1]?list1.) How do you write code that means "a list with one element, where that element islist1"?