Why this regular expression is not working in PHP but works in .net?

Question

Below is a regex which works fine in .net but give me error if I use it in PHP.

(?<=")([^"]+,[^"]+)?(?=")

What does this regex is supposed to return?

Input: 1,"x1",43,"tr","y,7"

It will return me "y,7" in this case. In general, it will return any part between " and " if it has a comma between it.

When I try to use this in PHP, I get following error:

Unknown modifier '('

Please help.

zerkms · Accepted Answer · 2011-01-15 12:36:01Z

2

~(?<=")([^"]+,[^"]+)?(?=")~

For php (preg_* functions) you need to specify delimiter around the regex iteself. It can be !, /, #, ~, etc.

answered Jan 15, 2011 at 12:36

zerkms

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4 Comments

Felix Kling Over a year ago

Can be even (...). That is why PHP throws this error, it thinks the expression is (?<=") and the following ( is not a valid modifier.

Mihir Over a year ago

Array ( [0] => 1,"x1",43,"tr"," [1] => " ) Array ( [0] => 1,"x1",43,"tr"," [1] => " ) I need "y,7" in result.

zerkms Over a year ago

@Mihir: debug it, then. Rewrite it from the scratch.

Felix Kling Over a year ago

@Mihir: Works fine for me: preg_match_all('~(?<=")([^"]+,[^"]+)?(?=")~','1,"x1",43,"tr","y,7"', $a); You might want the first character group match non-greedy: [^"]+? or add , to it.

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