Python2.7 TypeError: 'float' object cannot be interpreted as an index [duplicate]

Question

I just fork clone a repo inconvergent/hyphae on github to reuse hyphae.py with an update from python2.6 to python2.7 (and then 3.5) I fixed some error due to update but i still have TypeError for now.

Done

Update from python2.6 to pyton2.7.13 by adding () after all print

Fix

File "/home/user/hyphae/hyphae.py", line 378
main()
^
IndentationError: expected an indented block

By adding 2 whitespace

When do python2.7 /home/user/hyphae/hyphae.py with terminal

()
('filename', 'generations_a')
('SIZE', 15000)
('ZONEWIDTH', 80.0)
('RAD', 0.002666666666666667)
('ZONES', 187)
('one', 6.666666666666667e-05)
Traceback (most recent call last):
File "/home/user/hyphae/hyphae.py", line 378, in <module>
main()
File "/home/user/hyphae/hyphae.py", line 203, in main
R = np.zeros(NMAX,'float')
TypeError: 'float' object cannot be interpreted as an index

I not that few questions were asked about TypeError: 'float' object cannot be interpreted as an index in stackoverflow, e.g Here ot there, but as the noob as i'm, i don't find how to solve the matter.

Kevin · Accepted Answer · 2017-11-30 14:06:03Z

2

NMAX = 2*1e7 # maxmimum number of nodes

NMAX is a floating point number. In older versions of numpy, you can call zeros with a float as an argument. But this behavior is deprecated, and no longer works in the most recent version.

Try converting NMAX to an integer.

NMAX = int(2*1e7) # maxmimum number of nodes

answered Nov 30, 2017 at 14:06

Kevin

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