Mock created using PHPUnit return "NULL" when class was called

Question

Code:

$mockObject = $this->getMock('ORM_User');

$mockObject->expects($this->at(0))
    ->method('xxx')
    ->with($this->equalTo('a'))
    ->will($this->returnValue('aaa'));

$mockObject->expects($this->at(1))
    ->method('xxx')
    ->with($this->equalTo('b'))
    ->will($this->returnValue('bbb'));

var_dump("-".$mockObject->xxx('a'));
var_dump($mockObject->xxx('b'));  

$tmp = new ORM_User();
var_dump($tmp->xxx('a'));
var_dump($tmp->xxx('b'));

Output:


string(4) "-aaa"
string(3) "bbb"
NULL
NULL

In your code mock returns data, and real object returns nulls. — zerkms
– zerkms, Commented Jan 27, 2011 at 4:00

edorian · Accepted Answer · 2011-01-27 08:55:21Z

3

The does to exactly what you tell it too and works fine as far as i can see it.

You create a "fake" ORM_User and tell the xxx function to return "aaa" and "bbb" and it does that.

Then you create a real ORM_USER and call it, that returns null but that is behond the scope of phpunit. You are just calling the real class there to i don't see where you are getting at this that.

Maybe tell us what you are trying to do ?

answered Jan 27, 2011 at 8:55

edorian

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3 Comments

KingCrunch Over a year ago

Additional: It seems, that you (Felipe) use __call() to catch all calls to undefined methods and return null. If not, you should think about your naming conventions for methods (xxx() is not a good name).

Felipe Cardoso Martins Over a year ago

KingCrunch, the name "xxx" only was a example :D

Felipe Cardoso Martins Over a year ago

edorian, I finally do it... Thank's

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