I'm reading a list of email addresses from a config file. The addresses can be delimited by comma or semicolon - e.g.,
[email protected],[email protected], [email protected]
[email protected];[email protected]; [email protected]
I'd like to get rid of any whitespace around the email addresses too.
I need to get them into a Python list like this:
['[email protected]', '[email protected]', '[email protected]']
What's the most Pythonic way to do it? Thanks.
In this case I whould use the re module
>>> import re
>>>
>>> data = "[email protected];[email protected]; [email protected]"
>>> stuff = re.split(r"\s*[,;]\s*", data.strip())
Regular expressions are powerful, and probably the way to go here; but for something as simple as this, string methods are OK too. Here's a terse solution:
[s.strip() for s in s1.replace(',', ';').split(';')]
Test output:
>>> s1 = "[email protected],[email protected], [email protected]"
>>> s2 = " [email protected];[email protected]; [email protected] "
>>> print [s.strip() for s in s1.replace(',', ';').split(';')]
['[email protected]', '[email protected]', '[email protected]']
>>> print [s.strip() for s in s2.replace(',', ';').split(';')]
['[email protected]', '[email protected]', '[email protected]']
If it's only ';' or only ',' and you know which, use string.split:
>>> 'adjifjdasf;jdiafjodafs;jdiajof'.split(';')
['adjifjdasf', 'jdiafjodafs', 'jdiajof']
http://docs.python.org/library/stdtypes.html#str.split
EDIT For whitespace you can also do:
>>> map(str.strip, 'adjifjdasf;jdiafjodafs ; jdiajof'.split(';'))
['adjifjdasf', 'jdiafjodafs', 'jdiajof']
You can use string.maketrans to replace multiple separators with spaces in a single pass
import string
data = "one two, three ; four "
stuff = [i for i in data.translate(string.maketrans(";,", " ")).split()]
print stuff # -> ['one', 'two', 'three', 'four']
You could do it using just Python's string manipulation facilities:
import string
s1 = "[email protected],[email protected], [email protected]"
s2 = "[email protected];[email protected]; [email protected]"
print s1.translate(string.maketrans(';',','), string.whitespace).split(',')
# ['[email protected]', '[email protected]', '[email protected]']
print s2.translate(string.maketrans(';',','), string.whitespace).split(',')
# ['[email protected]', '[email protected]', '[email protected]']
data = ''' [email protected],[email protected], [email protected]
[email protected];[email protected];\t \[email protected] '''
print repr(data),'\n'
import re
print re.findall('[^,\s;]+', data)
result
' [email protected],[email protected], [email protected] \n [email protected];[email protected];\t \[email protected] '
['[email protected]', '[email protected]', '[email protected]', '[email protected]', '[email protected]', '[email protected]']
notice the '\n' , '\t' and '\r' in this data
def gen_list(file_path):
read= open(file_path, "r")
split1= read.split(";")
new_list= []
for i in split1:
split2 = i.split(",")
split_list = [item.strip() for item in split2 if "@" in item]
new_list.extend(split_list)
return new_list
