Is there a way to replace all occurrences in string giving an array as a parameter in replace() method.
For example:
Having this string: "ABCDEFG"
And having this array: ['A','D','F']
It is possible to replace the same letters in the string with something else? Something like:
"ABCDEFG".replace(['A','D','F'], '')
So the final result be: "BCEG"
You can loop through your array:
var str = "ABCDEFG";
['A','D','F'].forEach(c => str = str.replace(c, '*'))
console.log(str);Kind of:
"ABCDEFG".replace(new RegExp(['A','D','F'].join("|")), '')
There is actually a way to do this from an Array.
You'll need to create a RegEx dynamically :
let arr = ['A','D','F'];
let expression = arr.join('|');
let rx = new RegExp(expression, 'g');
console.log("ABCDEFG".replace(rx,''));If you want an array as input:
'ABCDEF'.replace(new RegExp(['A','D','F'].join('|'), 'g'), '')
By using the 'g' flag, it will replace all occurrences of 'A', 'D' or 'F' in the string.
You could also do this in a simpler way:
'ABCDEF'.replace(/A|D|F/g, '')
Here's a general function that uses regex similar to the other answers, but allows you to pass in whatever replacement string you like:
const str = 'ABCDEFG';
const arr = ['A', 'D', 'F'];
function replace(str, arr, r) {
const regex = new RegExp(arr.join('|'), 'g');
return str.replace(regex, p => r);
}
console.log(replace(str, arr, ''));
console.log(replace(str, arr, 'bob'));
"ABCDEFG".replace(/A|D|F/g, '')would be fine, or it has to be dynamic with the array ?replacemethod (given you don't want to touch the prototype). You could write your own function, though