I need to take a string input and count the occurrence of a character only once per character(should not repeat for the same character) and print it in a list or set or tuple. But I'm not getting the desired result.
Code:
string1 = input('Enter your string: ')
for letter in string1:
string2 = string1.count(letter,0)
ss = str(string2)
print(ss)
Output:
Enter your string: ggddg
3
3
2
2
3
Depending on how you want your output to look, you can use collections.Counter, which has a dict-like interface:
from collections import Counter
user_input = input('Enter your string: ')
counts = Counter(user_input)
print(counts) # prints: Counter({'g': 3, 'd': 2})
You are printing the count for each different character as many times as they appear in the string. First is g, there are 3 gs so you print 3, then another g comes and you count and print again. I think you want to print that there are 3 'g' and 2 'd'.
Try this:
letters = {}
for c in input("Enter your string: "):
if c not in letters:
letters[c] = 1
else:
letters[c] += 1
print(letters)
Output:
Enter your string: ggddg
{'g': 3, 'd': 2}
I think this is what you want, try it with the sample user string
#!python3
# sample user string: fdshjkfdskhjlfdsjklfdsevcxzm,.czxm,.
user_string = input('Enter your string: ')
all_letters = []
unique_letters = []
for letter in user_string:
all_letters.append(letter)
for unique in all_letters:
if unique in unique_letters:
pass
else:
unique_letters.append(unique)
for item in unique_letters:
print(item + ' = ' + str(all_letters.count(item)))
# results
'''
f = 4
d = 4
s = 4
h = 2
j = 3
k = 3
l = 2
e = 1
v = 1
c = 2
x = 2
z = 2
m = 2
, = 2
. = 2
'''
@Mahesh, counting occurrences of a character in a string can be efficiently done by using set and dictionary as follows.
Try it online at http://rextester.com/KQV63040.
Note: I have used
jsonmodule to pretty print the dictionary.You can use
OrderedDictofcollectionsmodule to retain the order of keys in dictionary based on insertion.
import json
string1 = input('Enter your string: ').strip()
unique_letters = set(string1)
letters_occurrences = {}
for letter in unique_letters:
letters_occurrences[letter] = string1.count(letter)
print() # newline
# Pretty printing the dictionary
print(json.dumps(letters_occurrences, indent=4))
» Output
Enter your string: abbacddabbc
{
"b": 4,
"a": 3,
"d": 2,
"c": 2
}
Try this:
string1 = input('Enter your string: ')
print('\n'.join(list(set([i+' '+str(string1.count(i)) for i in string1]))))
Output:
Enter your string: aaabbcca
c 2
a 4
b 2
Or try this:
string1 = input('Enter your string: ')
print('\n'.join(list(set(map(lambda x: x+' '+str(string1.count(x)),string1)))))
Output:
Enter your string: aaabbcca
c 2
a 4
b 2
you could use a dict to storage that info
d = {}
for c in string1:
try:
d[c] += 1
except KeyError:
d[c] = 1
print(d)
