call bash script with arguments in python

Question

I am trying to execute the following via a python script. But I am getting an error. Unknown option:-a test -b 25 -c 18 --d 25 23

script_args = '-a test -b 25 -c 18 --d 25 23'
subprocess.Popen(['/home/pi/bash/bash_script.sh', script_args])

I can copy the unknown option line and execute my script and the script runs without any errors and I am getting desired output.

 /home/pi/bash/bash_script.sh -a test -b 25 -c 18 --d 25 23

What am I doing incorrectly via the python script?

Ignacio Vazquez-Abrams · Accepted Answer · 2018-07-23 16:18:39Z

3

You're passing a single argument composed of all those characters.

script_args = ['-a', 'test', ..., '23']
subprocess.Popen(['/home/pi/bash/bash_script.sh'] + script_args)

answered Jul 23, 2018 at 16:18

Ignacio Vazquez-Abrams

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1 Comment

Håken Lid Over a year ago

You can also unpack arguments into a list using the * operator which, unlike +, supports all iterable types. subprocess.run(['/home/pi/bash/bash_script.sh', *script_args])

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