Transform recursive function to recursive arrow function

Question

I have the following code with a recursive function which I would like to transform to recursive arrow function:

const hasAccess = menuSections.some(function s(x) {
  if (x.link === route.routeConfig.path) {
    return true;
  }

  if (x.sections) {
    return (x.sections.some(s));
  }

  return false;
});

Any idea on how to do it?

Why? The function doesn't use this, arguments or anything else that would be handled differently by an arrow function. It does use its own name to recurse, and arrow functions are anonymous. For your problem a function expression has benefits over an arrow function but an arrow function has no benefits at all over a function expression. — Quentin
– Quentin, Commented Oct 4, 2018 at 9:11

Nina Scholz · Accepted Answer · 2018-10-04 09:19:57Z

1

You could use an own function for callback and shorten the conditions for the return value.

const 
    check = x => x.link === route.routeConfig.path || x.sections && x.sections.some(check),
    hasAccess = menuSections.some(check);

edited Oct 4, 2018 at 9:19

answered Oct 4, 2018 at 9:13

Nina Scholz

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2 Comments

RobG Over a year ago

It possibly should be !!x.sections so that, per the OP, it returns a boolean rather than undefined, or null, or 0 or ….

Nina Scholz Over a year ago

it is a callback used in some, so any falsy value works.

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