Unittest failed in Python IDE PyCharm

Question

I tried to make a simple unittest in Python, but I don't know why the test failed. I have made three files:

name_function.py in which I have a function that receive two parameters (first name, last name) and return the concatenated name.

        def get_formatted_name(first, last):
            full_name = first + ' ' + last
            return full_name.title()

names.py in which the user is asked to enter the first name and last name or q to quit. After that the function get_formatted_name is called and concatenated name is printed.

        from name_function import get_formatted_name
    
        print("\n Enter 'q' at any time to quit.")
        while True:
            first = input("\n Please give me a first name : ")
            if first == 'q':
                break
            last = input("\n Please give me a second name : ")
            if last == 'q':
                break
    
        formatted_name = get_formatted_name(first, last)
        print("\n\t Neatly formatted name : " + formatted_name + '.')

test_name_function.py where the function is tested.

        import unittest  
        from name_function import get_formatted_name  
 
        class NamesTestCase(unittest.TestCase):  
            def test_first_last_name(self):  
                formatted_name = get_formatted_name('Clint', 'Eastwood')  
                self.assertEqual(formatted_name, 'Clint Eastwood')  

        unittest.main()

In this window, I run cmd command (see attach Capture_1).
In cmd I run the command (see attach Capture_2 and Capture_3).
I don't understand where is my mistake? In Capture_3 see what I obtain when I run the test.
I use Python 3.7.2 and the IDE Python that I use is PyCharm.

Capture_1 Capture_2 Capture_3

Zykerd · Accepted Answer · 2019-02-26 23:33:26Z

1

Your code looks good to me. I ran it on my machine and it works great. The only thing I noticed is python -m unittest does not find your test. A quick workaround would be to add the following at the end of your unittest file.

if __name__ == '__main__':
    unittest.main()

Then, you can run it with the following command. python test_name_function.py

answered Feb 26, 2019 at 23:33

Zykerd

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1 Comment

John Szakmeister Over a year ago

I think the problem is that without the guard, unittest.main() is being called again when the test file is imported and is doing a sys.exit(1) internally which results in the error.

Grismar · Accepted Answer · 2019-02-27 00:25:48Z

0

Since you are asking about PyCharm specifically, here's all you need for that:

remove the last line from your unit test file: unittest.main()
or do what @Zykerd suggested and turn it into

This:

if __name__ == '__main__':
    unittest.main()

rightclick the test in PyCharm and select Run Unittests in test_name_function

Both work (i.e. without the call to main, or with the call behind the main name check.

answered Feb 27, 2019 at 0:25

Grismar

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2 Comments

mircead Over a year ago

Thank you Grismar.

Grismar Over a year ago

You're welcome - if the answer answered your question, please accept it with the checkmark so the question is marked answered.

CodeNinja · Accepted Answer · 2019-02-27 14:26:46Z

0

This is because it is assumed that you are running on the interactive interpreter and at the point of the exception it fails with a SystemExit. However, Like mentioned in the comment from @Zykerd the

if __name__ == '__main__':
    unittest.main()

above would solve this problem by assuming that the script is being run from the command line instead of interactive interpreter.

Cheers!

Please check here for further explanation : Tests succeed, still get traceback

answered Feb 27, 2019 at 14:26

CodeNinja

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