How to properly format if/else indentations in python?

Question

I'm doing a basic programming problem in regards to decision statements. The code should relate to three types of fish with different options whenever each option is inputted. I think most of my code runs properly, except I'm not sure how to format the final, catch-all else that absorbs all incorrect inputs.

My current code works well but the else statement at the bottom is tacked onto every response I give outside of the first input in the solution.

if fish_type == "carnivorous":
    fish_size = str(input("Do you have smaller fish already? "))
    if fish_size == "yes":
        print("This is a bad idea! It'll eat the little ones!")
    if fish_size == "no":
        print("Great! Enjoy!")
if fish_type == "salt water":
    print("Wow, you're a fancy fish parent!")
if fish_type == "community":
    fish_number = int(input("How many fish of this species do you already have?\
 "))
    if fish_number < 3:
        print("You should get more than one fish!")
    else:
        print("Yay, more friends!")
else:
    print("I don't think that's a type of fish; maybe you're looking for a \
lizard?")

For example, if I input "carnivorous" I am routed correctly to the carnivorous if statements, but when I answer "yes" or "no" my else statement is formatted incorrectly. Thanks for your help!

Do you need 3 ifs for 3 fish_type? Do you meant to use elif for salt water and community? — kuro
– kuro, Commented Sep 20, 2019 at 5:07
Also, can someone explain the use of if name == 'main': as a formatting thing? — DysDiv
– DysDiv, Commented Sep 20, 2019 at 5:07
the second check should be elif or else. You seem to have multiple if's instead — moys
– moys, Commented Sep 20, 2019 at 5:09
@kuro I think I could have used elif in order to straighten up the code — DysDiv
– DysDiv, Commented Sep 20, 2019 at 5:09
For the second query look at stackoverflow.com/questions/419163/what-does-if-name-main-do — kuro
– kuro, Commented Sep 20, 2019 at 5:10

ParalysisByAnalysis · Accepted Answer · 2019-09-20 05:21:15Z

1

Your issue may have been the way the print statements were formatted. The below code works.

fish_type = 'not_a_fish'

if fish_type == "carnivorous":
    fish_size = str(input("Do you have smaller fish already? "))
    if fish_size == "yes":
        print("This is a bad idea! It'll eat the little ones!")
    elif fish_size == "no":
        print("Great! Enjoy!")
elif fish_type == "salt water":
    print("Wow, you're a fancy fish parent!")
elif fish_type == "community":
    fish_number = int(input("How many fish of this species do you already have?\n"))
    if fish_number < 3:
        print("You should get more than one fish!")
    else:
        print("Yay, more friends!")
else:
    print("I don't think that's a type of fish; maybe you're looking for a \n lizard?")

answered Sep 20, 2019 at 5:21

ParalysisByAnalysis

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