Python Print objects in class

Question

So I have list of objects in class and I need to print all different songs from one singer. So far I have this code and I am not sure is it correct

Also I need to use recursion method

def allmusic(listofobjects, name):
    nameandsurname=self.name
    if(listofobjects.name==nameandsurname):
        print(listofobjects.music)
        return(listofobjects(music[1:]))
    else:
        return(listofobjects(name[1:]))

Also I need to print number of singers in that class and code I have is

def allmusic(listofobjects):
    numberofsingers=0
    for s in listofobjects:
       numberofsingers+=1
       return(listofobjects()[1:])
    print(numberofsingers)

What is self supposed to refer to in the first attempt? What do the elements of the input list look like? — chepner
– chepner, Commented Jun 26, 2020 at 13:16
So i have init method class Music def __init__(self,music,year,howlong,typeofmusic,nameofsinger): self.music=music self.year=year self.howlong=howlong self.typeofmusic=typeofmusic self.nameofsinger=nameofsinger — Minko
– Minko, Commented Jun 26, 2020 at 13:21
You need to add self in every function argument inside the class. — lil_noob
– lil_noob, Commented Jun 26, 2020 at 13:28
So i think when you create def method its already in class and you dont need to type everytime self — Minko
– Minko, Commented Jun 26, 2020 at 13:30
Refer to this link. google.com/amp/s/www.geeksforgeeks.org/self-in-python-class/amp — lil_noob
– lil_noob, Commented Jun 26, 2020 at 13:37

faiz-e · Accepted Answer · 2020-06-26 14:32:32Z

1

I think this is what you want. It recursively prints the all songs of a specific singer provided in the arguments. Here listOfMusic is the list of Music objects.

def PrintSinger(self, listOfMusic, name):
        if(listOfMusic[0].nameOfSinger == name):
            print(listOfMusic[0].music)
        if(len(listOfMusic) ==  1):
            return
        else:
            return self.PrintSinger(listOfMusic[1:], name)

answered Jun 26, 2020 at 14:32

faiz-e

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