Method reference to an instance method of an arbitrary object of a particular type [duplicate]

Question

String[] arr = {"First", "Second", "Third", "Fourth"};
Arrays.sort(arr, String::compareToIgnoreCase); //can compile
Arrays.sort(arr, "a"::compareToIgnoreCase); //can't compile

why the "a"::compareToIgnoreCase cannot compile? if we can said String::compareToIgnoreCase has an implicit String argument (this), why we cannot said "a"::compareToIgnoreCase has an implicit "a" as argument? ("a" compare to "First", "a" compare to "Second".....)

Eran · Accepted Answer · 2020-08-16 12:01:16Z

2

"a"::compareToIgnoreCase is a method reference to a method of a single argument, which compares a given String to the String "a". The implicit argument is always equal to "a".

A Comparator's Compare method requires two given String instances.

Maybe if you write the method references as lambda expressions it would be clearer:

Arrays.sort(arr, (a,b) -> a.compareToIgnoreCase(b)); //can compile

Arrays.sort(arr, (x) -> "a".compareToIgnoreCase(x)); // can't compile, since a method with 
                                                     // two arguments is expected

answered Aug 16, 2020 at 12:01

Eran

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1 Comment

user1169587 Over a year ago

Yes, think in lambda expression is always clearer than method reference

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