I have this JSON string value as defined below. I want to get he value for "code" only. I tried the solution in the internet but I am only getting a null value. Any idea on this?
JObject json = JObject.Parse(JSON string here);
var jsonData = json.SelectToken("serviceMessage.code"); <-- THIS RETURNS NULL
The json:
{
"highestSeverity":"Error",
"serviceMessage":[
{
"code":"3004",
"severity":"Error",
"reason":"Reason here."
}
]
}
Basically you can parse it to a model and get the value for code. E.g:
public class ServiceMessage
{
public string code { get; set; }
public string severity { get; set; }
public string reason { get; set; }
}
public class Root{
public string highestSeverity { get; set; }
public List<ServiceMessage> serviceMessage { get; set; }
}
public class AnotherClass
{
public string MyFunction(string myJson){
var data = JsonConvert.DeserializeObject<Root>(myJson);
//Then you can access the value in the object
return data.serviceMessage.FirstOrDefault().code;
}
}
"serviceMessage" is indeed a list of objects...yes. It's a list. It's not an object. In JSON, objects are surround by { }, lists are surrounded by [ ]. and the way you parse them and access the items within them is different. And it isn't the outer item because it's a named property inside the enclosing outer object. Even your hasty edit to add a "list" to the deserialisation doesn't help because you're still targeting only part of the object, and your method now tries to access the "code" property of a list.As serviceMessage is an array, assuming you want the first item you can simply use
var code = json["serviceMessage"][0]["code"];
Live example: https://dotnetfiddle.net/2WgkcF
As it was indicated by ADyson your serviceMessage in an array not an object. So, you have to treat it as a collection.
code valueJObject json = JObject.Parse(rawJson);
JArray messages = (JArray)json["serviceMessage"];
string code = messages.FirstOrDefault()?["code"]?.Value<string>()
serviceMessageis an array . Therefore it doesn't have a "code" property, but the first item within the array does...