php regex lookahead - exclude character

Question

I’m trying to extract three parts with a regular expression. It works for the controller and the id but not for the slug, I can not remove the last -

    <?php
    $url = "/cockpit/posts/my-second-article-2-155";
    $routes = [];
    $patterns = "/(?<controller>[a-z]+)\/(?<slug>[a-z0-9\-]+)(?<=\-)(?<id>[0-9]+)/i";
    
    preg_match($patterns, $url, $matches);
    foreach ($matches as $key => $value){
        if(!is_numeric($key)){
            $routes[$key] = $value;
        }
    }
    
    var_dump($routes);

I get the following result :

array(3) {
  ["controller"]=>
  string(5) "posts"
  ["slug"]=>
  string(20) "my-second-article-2-"
  ["id"]=>
  string(3) "155"
}

But i want this slug :

["slug"]=>
  string(20) "my-second-article-2"

Thanks

Tim Biegeleisen · Accepted Answer · 2022-09-21 14:32:20Z

0

You may use the following regex pattern:

/(?<controller>[a-z]+)\/(?<slug>[a-z0-9]+(?:-[a-z0-9]+)+)-(?<id>[0-9]+)/i

Your updated PHP script:

$url = "/cockpit/posts/my-second-article-2-155";
$routes = [];
$patterns = "/(?<controller>[a-z]+)\/(?<slug>[a-z0-9]+(?:-[a-z0-9]+)+)-(?<id>[0-9]+)/i";

preg_match($patterns, $url, $matches);
foreach ($matches as $key => $value) {
    if (!is_numeric($key)) {
        $routes[$key] = $value;
    }
}

var_dump($routes);

This prints:

array(3) {
  ["controller"]=>
  string(5) "posts"
  ["slug"]=>
  string(19) "my-second-article-2"
  ["id"]=>
  string(3) "155"
}

The final portion of the updated regex says to match:

[a-z0-9]+ alphanumeric term
(?:-[a-z0-9]+)+ followed by hyphen and another alphanumeric term, both 1 or more times
- match a literal hyphen
[0-9]+ match the id

answered Sep 21, 2022 at 14:32

Tim Biegeleisen

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