The default values of a function on Python is not working

Question

I'm starting to study Python functions, and I have a problem that it seems correct to me but it isn't working.

I want to show two informations typed. Jogador (player) and Gols (Score), when I type the 2 inputs it works very well, but I want to have two default parameters and this is not working, can someone help me, what am I doing wrong? `

def ficha(nome="<desconhecido>", gols=0):
    return f'O jogador {nome} fez {gols} gol(s) no campeonato.'


jog = input('Nome do jogador: ')
gol = input('Número de gols: ')
print(ficha(jog, gol))

`

I'm expecting to shows the default parameters when nothing is typed by the user.

nokla · Accepted Answer · 2022-12-10 13:53:26Z

1

def ficha(nome=None, gols=None):
    if not nome:
        nome = "<desconhecido>"
    if not gols:
        gols =0
    return f'O jogador {nome} fez {gols} gol(s) no campeonato.'


jog = input('Nome do jogador: ')
gol = input('Número de gols: ')
print(ficha(jog, gol))

When you don't enter anything to the input, it saves "". When you send it to the function it gets "" and replace it with the default arguments. If you want your function to use the default parameters, just don't send them to the function.

Use: ficha()

answered Dec 10, 2022 at 13:53

nokla

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3 Comments

John Coleman Over a year ago

What is the motivation for replacing the default values with None? That works of course, but might leave OP with the impression that it was required to solve the problem. The rest of your answer explains what the true problem is,

nokla Over a year ago

I just didn't want to repeat the same definition. That way, whether the function receives "" or nothing, it get defined at the ifs part.

Uatilla Viana Almeida Over a year ago

Thanks a lot, both of you. I got how the def function works when the user types nothing, it replaces the default parameter with none. Again thank you a lot!!

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