regex for accepting spaces only between words

Question

I am trying to create a regular expression where the user should enter just a word or words with space between them and its length must have a limit [1 to 32].

For instance, it should accept below line;

wordX[space]wordX[space][space][space]wordX

but it should not accept that:

[space]wordX or wordX[space] or only [space]

wordX must be compatible with this regex:

^(([0-9A-Za-z!"#$%'()*+,./:;=?@^_`{|}~\\\[\]-]))$

Kirill Polishchuk · Accepted Answer · 2011-09-21 14:03:11Z

1

Try this:

^(?:\w+\s){0,31}\w+$

\w means: digits, letters, underscore

For strictly accepted chars:

^(?:[\w!"#$%'()*+,./:;=?@^_`{|}~\\\[\]]+\s){0,31}[\w!"#$%'()*+,./:;=?@^_`{|}~\\\[\]]+$

Or:

^(?:\S+\s){0,31}\S+$

\S - any character other than whitespace

Update:

If word length is between 1 and 32 than use this regex:

^(?:\w{1,31}\s)*\w{1,31}$

In the same manner you can modify other regexes.

edited Sep 21, 2011 at 14:03

answered Sep 21, 2011 at 13:43

Kirill Polishchuk

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5 Comments

Onur Over a year ago

thanks but limit is not working. I tested on this page: tools.netshiftmedia.com/regexlibrary

Onur Over a year ago

just anything more than 32 characters. it accepts any word without limit.

Kirill Polishchuk Over a year ago

@onuR, Is it word length limit or words count limit?

Onur Over a year ago

thanks a lot. I have one more issue, how can check total length of the phrase not only a word?

Kirill Polishchuk Over a year ago

@onuR, Try this ^(?=.{40,100}$)(?:\w{1,31}\s)*\w{1,31}$ From 40 to 100 chars. I don't know, does your regex engine support lookahead...

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