I am new to programming and I came across these two similar problems:
for i in range(10):
if i == 5:
break
else:
print(i)
else:
print("Here")
Output:
0 1 2 3 4
for i in range(5):
if i == 5:
break
else:
print(i)
else:
print("Here")
Output:
0 1 2 3 4 Here
The second example is executing the else statement also. Why?
From this link it explains that for loops can have an else statement.
From the link:
The else clause executes after the loop completes normally. This means that the loop did not encounter a break statement.
So in your first example the loop hits the break point and so doesn't execute the else clause print("Here"). In the second example the last value of i in the loop is 4 so the break is never hit.
# Example 1
for i in range(10):
if i == 5:
print("Break")
break
else:
print(i)
else:
print("Here")
# Output: 0 1 2 3 4 Break
# Example 2
for i in range(5):
if i == 5:
print("Break")
break
else:
print(i)
else:
print("Here")
# Output: 0 1 2 3 4 Here
# Another example that doesn't cause break
for i in range(3):
if i == 5:
print("Break")
break
else:
print(i)
else:
print("Here")
# Output: 0 1 2 Here
In python, we can use any loop and else. If the loop breaks, then else statement will not be executed. Else will be executed when the loop doesn't break.
For more ref: https://www.geeksforgeeks.org/using-else-conditional-statement-with-for-loop-in-python/
Correcting post the comment from @Slothrop
elsedoesn't always pair withif. It can also go with afororwhileloop, or atry...exceptconstruction.else:in aforloop meansif no break. They just did not want to introduce a new keyword.