python subprocess calling the local interpreter instead of the linked one

Question

I am attempting to execute a function within a Python script as a subprocess using its own interpreter, specified in the subprocess.run() call. This interpreter may include packages not present in my local Python environment. When I debug the file, errors occur due to these missing libraries in my local python instead of the one linked in the command. Am I misunderstanding something?

try:
    proc = subprocess.run(
        [
            r'C:\Users\user\AppData\Local\Programs\Python\Python311\python.exe',
            r'C:\subprocess_python\my_file_subprocess.py',
            str(self.x), str(self.y), str(self.z)
        ],
        capture_output=True,
        check=True
    )
except subprocess.CalledProcessError as proc_err:
    print("An exception occurred in the subprocess: \n ", proc_err)
    print("stdout : \n", proc_err.stdout.decode())
    print("stderr : \n", proc_err.stderr.decode())
    exit(1)

Can you explain what you mean by "local interpreter" vs. "linked interpreter"? Those aren't standard terms, and it's unclear what you mean by them. — ShadowRanger
– ShadowRanger, Commented Mar 7, 2024 at 14:54
"When I debug the file, errors occur due to these missing libraries in my local python instead of the one linked in the command." I'd need to see proof of that. I suspect you are misinterpreting whatever error message you are getting, or that you aren't correctly identifying which packages my_file_subprocess.py requires. — chepner
– chepner, Commented Mar 7, 2024 at 15:05
@chepner: It's also possible they did something terrible like define a PYTHONPATH environment variable (which is used by all Python's that launch) rather than installing things properly per-interpreter. — ShadowRanger
– ShadowRanger, Commented Mar 7, 2024 at 20:32
@ShadowRanger by linked one the one whose path is in the subprocess\.run() command and by local i mean the local IDE where I am calling this subprocess.run() file — Novice_Developer
– Novice_Developer, Commented Mar 8, 2024 at 6:13
@chepner I am pretty confident about the packages , whenever I run the file my_file_subprocess.py , it works just fine with all the packages it needs are available in the system interpreter , but whenever I dubug while calling it form the subprocess , it only complains about the package missing which is not available in the local intepreter that I am using to call this subprocess.run command — Novice_Developer
– Novice_Developer, Commented Mar 8, 2024 at 6:15

Mikaelblomkvistsson · Accepted Answer · 2024-03-07 12:53:17Z

0

Use sys.executable to determine what's the path of currently ran interpreter.

answered Mar 7, 2024 at 12:53

Mikaelblomkvistsson

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2 Comments

Novice_Developer Over a year ago

sys.executable returns the path for the linked one but pkgutil.iter_modules() returns the path of the local interpreter

Mikaelblomkvistsson Over a year ago

pkgutil.iter_modules() is a generator that list of ModuleInfo objects, not a single path

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