9

I could pass one-dimension array to python like below. and I wonder if I can pass c++ double pointer array to python by using ctypes, numpy.

test.cpp:

#include <stdio.h>
extern "C" void cfun(const void * indatav, int rowcount, int colcount, void * outdatav);

void cfun(const void * indatav, int rowcount, int colcount, void * outdatav) {
    //void cfun(const double * indata, int rowcount, int colcount, double * outdata) {
    const double * indata = (double *) indatav;
    double * outdata = (double *) outdatav;
    int i;
    puts("Here we go!");
    for (i = 0; i < rowcount * colcount; ++i) {
        outdata[i] = indata[i] * 4;
    }
    puts("Done!");
}

test.py:

import numpy
import ctypes

indata = numpy.ones((5,6), dtype=numpy.double)
outdata = numpy.zeros((5,6), dtype=numpy.double)
lib = ctypes.cdll.LoadLibrary('./ctest.so')
fun = lib.cfun
# Here comes the fool part.
#fun(ctypes.c_void_p(indata.ctypes.data), ctypes.c_void_p(outdata.ctypes.data))

fun(ctypes.c_void_p(indata.ctypes.data), ctypes.c_int(5), ctypes.c_int(6),
    ctypes.c_void_p(outdata.ctypes.data))


print 'indata: %s' % indata
print 'outdata: %s' % outdata
3
  • This is a hack I have been taught, but why not just pass the pointers as long integers ? Commented Jan 9, 2012 at 3:58
  • because the type can be double.. etc not only integer. Commented Jan 9, 2012 at 17:14
  • The pointers can always be represented as long integers. and then cast back to whatever type you want. Commented Jan 16, 2012 at 15:30

1 Answer 1

8

Here's a way. I didn't see a nice way to use numpy with double**.

test.cpp (Windows)

#include <stdio.h>

extern "C" __declspec(dllexport) void cfun(const double ** indata, int rowcount, int colcount, double ** outdata) {
    for (int i = 0; i < rowcount; ++i) {
        for (int j = 0; j < colcount; ++j) {
            outdata[i][j] = indata[i][j] * 4;
        }
    }
}

test.py

import numpy
import ctypes

# Allocate array of double*
indata = (ctypes.POINTER(ctypes.c_double) * 5)()
for i in range(5):
    # Allocate arrays of double
    indata[i] = (ctypes.c_double * 6)()
    for j in range(6):
        indata[i][j] = 1.0

outdata = (ctypes.POINTER(ctypes.c_double) * 5)()
for i in range(5):
    outdata[i] = (ctypes.c_double * 6)()
    for j in range(6):
        outdata[i][j] = 1.0

lib = ctypes.cdll.LoadLibrary('test')
fun = lib.cfun

def dump(a,rows,cols):
    for i in range(rows):
        for j in range(cols):
            print a[i][j],
        print

dump(indata,5,6)
fun(ctypes.byref(indata),5,6,ctypes.byref(outdata))
dump(outdata,5,6)

Output

1.0 1.0 1.0 1.0 1.0 1.0
1.0 1.0 1.0 1.0 1.0 1.0
1.0 1.0 1.0 1.0 1.0 1.0
1.0 1.0 1.0 1.0 1.0 1.0
1.0 1.0 1.0 1.0 1.0 1.0
4.0 4.0 4.0 4.0 4.0 4.0
4.0 4.0 4.0 4.0 4.0 4.0
4.0 4.0 4.0 4.0 4.0 4.0
4.0 4.0 4.0 4.0 4.0 4.0
4.0 4.0 4.0 4.0 4.0 4.0
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6 Comments

I got an error while creating ".so" file test.cpp:4:1: error: expected constructor, destructor, or type conversion before ‘(’ token
it works fine without "__declspec(dllexport)". thanks and in fortran, multi-dimensional array can be passed directly with numpy right? fwrap.. actually I am looking for passing array among python <-> c,c++ <-> fortran.
Yes, __declspec(dllexport) is Windows-specific to export a function from a dynamic library. The code you posted works as is (with minor mods for Windows, for me) with a double pointer and multi-dimensional array. You don't need all that casting, though. What exactly is your question?
I haven't touched Fortran for years so can't help there. I'll note that if you write your original C++ function with double* instead of void* you can pass _____.ctypes.data directly without the ctypes.c_void_p wrappers. You also can pass 5,6 instead of ctypes.c_int(5),ctypes.c_int(6).
Is there a way to pass this array by using numpy? I want to use numpy not only using ctypes.
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