I have filefield in my django model:
class MyModel(Model):
file = models.FileField(upload_to='attachment/%Y/%m/%d',max_length=480)
This file will display in the web page with link "http://test.com.cn/home/projects/89/attachment/2012/02/24/sscsx.txt"
What I want to do is when user click the file link, it will download the file automatically; Can anyone tell me how to do this in the view?
Thanks in advance!
You can try the following code, assuming that object_name is an object of that model:
filename = object_name.file.name.split('/')[-1]
response = HttpResponse(object_name.file, content_type='text/plain')
response['Content-Disposition'] = 'attachment; filename=%s' % filename
return response
See the following part of the Django documentation on sending files directly: https://docs.djangoproject.com/en/dev/ref/request-response/#telling-the-browser-to-treat-the-response-as-a-file-attachment
filename = os.path.basename(object_name.file.name). This will work regardless of OS.
https://docs.djangoproject.com/en/dev/ref/models/fields/#django.db.models.FileField.storage
All that will be stored in your database is a path to the file (relative to MEDIA_ROOT). You'll most likely want to use the convenience url function provided by Django. For example, if your ImageField is called mug_shot, you can get the absolute path to your image in a template with {{ object.mug_shot.url }}.
You can do this with a FileResponse like so:
def download_file_view(request, id):
object = get_object_or_404(MyModel, id)
# Create FileResponse
return FileResponse(
object.file.open(),
as_attachment=True,
filename=object.file.name
)