How to convert string with signed integer value to signed integer?

Question

I'm using int(myString), myString = "-1" and I get error:

ValueError: invalid literal for int() with base 10: '"-1"'

What's your Python version, 2.7 does int("-1") with no problem. Looks like your number is double quoted. Was able to reproduce it by int('"-1"') — German Rumm
– German Rumm, Commented Mar 1, 2012 at 13:09
Why define the myString after the conversion? Can you post all you code? — kev
– kev, Commented Mar 1, 2012 at 13:11

Jonas Byström · Accepted Answer · 2012-03-01 13:09:23Z

11

The string contains quotes, i.e.

s = '"-1"'

You need to get rid of the quotes, something like

s = '"-1"'
int(s.replace('"', ''))

should do the trick.

answered Mar 1, 2012 at 13:09

Jonas Byström

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1 Comment

alhcr Over a year ago

thanks, I'm modifying someones code so it wasn't that easy to notice, in fact I just guessed that there should be "-1" but there wasn't, and I have 1 hour of python programming experience ;)

aweis · Accepted Answer · 2012-03-01 13:09:08Z

2

Are you sure that you're string doesent look like "'-1'" and not "-1"

a = "'-1'"
print int(a)
>>> ValueError: invalid literal for int() with base 10: '"-1"'

a = "-1"
print int(a)
>>> -1

answered Mar 1, 2012 at 13:09

aweis

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Comments

avasal · Accepted Answer · 2012-03-01 13:11:24Z

1

In [2]: int(eval('"-1"'))
Out[2]: -1

answered Mar 1, 2012 at 13:11

avasal

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Comments

Open AI - Opting Out · Accepted Answer · 2012-03-01 13:13:23Z

1

>>> int("-1")
-1

>>> int('"-1"')

Traceback (most recent call last):
  File "<pyshell#1>", line 1, in <module>
    int('"-1"')
ValueError: invalid literal for int() with base 10: '"-1"'

>>> '"-1"'.strip('\"')
'-1'

answered Mar 1, 2012 at 13:13

Open AI - Opting Out

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Comments

warvariuc · Accepted Answer · 2012-03-01 13:41:07Z

1

str.strip method accepts characters. You can use it to get rid of surrounding quotes:

>>> int('"-1"'.strip('"'))
-1
>>>

answered Mar 1, 2012 at 13:41

warvariuc

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